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hodyreva [135]
3 years ago
11

Ava takes 5/6 minutes to run 1 lap around the track. If Ava runs around the track at the same pace for 1/4 hour, how many laps w

ill Ava run
Mathematics
1 answer:
viktelen [127]3 years ago
7 0

Answer:

18 laps

Step-by-step explanation:

5/6 of one minute is 50 seconds.

There are 3600 seconds in one hour, which means there are 900 seconds in 1/4 of an hour. (3600*1/4)

This would leave us with 900 seconds divided by 50 seconds per lap.

900/50=18

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7 0
3 years ago
Pls help fast this is khan academy
kvasek [131]

Answer:

A

Step-by-step explanation:

The two angles given are vertical angles because they are opposite of each other

4 0
3 years ago
Read 2 more answers
PLEASE HELP.. Sharlene purchased a new truck, whose value over time depreciates. Sharlene's truck depreciates according to the f
Gekata [30.6K]

Using it's concept, the range of the given exponential function is:

C. 0 < y ≤ 46638.

<h3>What is the range of a function?</h3>

The range of a function is the set that contains all possible output values for the function.

In this problem, the function is:

y = 46,638(0.78)^x.

It is an exponential function with initial value 46,638 and rate of change 0.78. Exponential functions that are not shifted down, such as this one, are never negative nor zero, hence the range also has the restriction y > 0, and is given by:

C. 0 < y ≤ 46638.

More can be learned about the range of a function at brainly.com/question/28388172

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4 0
2 years ago
Tom is 8 years older than jane. five yeara ago tom was three times as old as jane. how old is jane now?
Mumz [18]
Jane = x years

Tom = x+8

*5 Years Ago

Jane= x-5

Tom= (x+8)-5=>x+3---------------------------
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5 0
3 years ago
Compute the standard error for sample proportions from a population with proportion p= 0.55 for sample sizes of n=30, n=100 and
Pani-rosa [81]

Given Information:

Population proportion = p =  0.55

Sample size 1 = n₁ = 30

Sample size 2 = n₂ = 100

Sample size 3 = n₃ = 1000

Required Information:

Standard error = σ = ?

Answer:

$ \sigma_1 = 0.091 $

$ \sigma_2 = 0.050 $

$ \sigma_3 = 0.016 $

Step-by-step explanation:

The standard error for sample proportions from a population is given by

$ \sigma =  \sqrt{\frac{p(1-p)}{n} } $  

Where p is the population proportion and n is the sample size.

For sample size n₁ = 30

$ \sigma_1 =  \sqrt{\frac{p(1-p)}{n_1} } $

$ \sigma_1 =  \sqrt{\frac{0.55(1-0.55)}{30} } $

$ \sigma_1 = 0.091 $

For sample size n₂ = 100

$ \sigma_2 =  \sqrt{\frac{p(1-p)}{n_2} } $

$ \sigma_2 =  \sqrt{\frac{0.55(1-0.55)}{100} } $

$ \sigma_2 = 0.050 $

For sample size n₃ = 1000

$ \sigma_3 =  \sqrt{\frac{p(1-p)}{n_3} } $

$ \sigma_3 =  \sqrt{\frac{0.55(1-0.55)}{1000} } $

$ \sigma_3 = 0.016 $

As you can notice, the standard error decreases as the sample size increases.

Therefore, the greater the sample size lesser will be the standard error.

8 0
4 years ago
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