Which expression shows twice the sum of 8 and a number n?

grandymaker [24]

3421880 number of the different meals are possible.

<h3>What is the combination?</h3>

The arrangement of the different things or numbers in the number of the ways is called as the combination.

It is given that:-

Number of appetizers is 7, the number of entres is 10, and that there's 4 choices of desserts.

So let's take each course by itself. You can choose 1 of 7 appetizers. So we have n = 7 After that, you chose an entre,

so the number of possible meals to this point is

n = 7 x 10 = 70

Finally, you finish off with a dessert, so the number of meals is:

n = 70 x 4 = 280

Therefore the number of possible meals you can have is 280. Note: If the values of 77, 1010 and 44 aren't errors, but are actually correct, then the number of meals is

n = 77 x 1010 x 44 = 3421880

Therefore 3421880 different meals are possible.

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8 0

3 years ago

PLEASE I NEED HELP URGENT I Will MARKE YOU BRAIN LIST

navik [9.2K]

Answer:

$1) \frac{1}{(x - 3)(x + 2)} + \frac{3}{(x + 2)(4 - x)} + \frac{2}{(x - 3)(x - 4)} \\ \\ = \frac{x - 4}{(x - 3)(x + 2)(x - 4)} - \frac{3(x - 3)}{(x - 4)(x + 2)(x - 3)} + \frac{2(x + 2)}{(x + 2)(x - 3)(x - 4)} \\ \\ = \frac{x - 4 - 3x + 9 + 2x + 4}{(x - 3)(x - 4)(x + 2)} \\ \\ = \frac{9}{(x + 2)(x - 3)(x - 4)}$

$2) \frac{2}{(x - 2)(x - 3)} + \frac{2}{(x - 1)(3 - x)} + \frac{1}{(1 - x)(2 - x)} \\ \\ = \frac{2(x - 1)}{(x - 1)(x - 2)(x - 3)} - \frac{2(x - 2)}{(x - 1)(x - 2)(x - 3)} + \frac{x - 3}{(x - 1)(x - 2)(x - 3)} \\ \\ = \frac{2x - 2 - 2x + 4 + x - 3}{(x - 1)(x -2)(x - 3)} \\ \\ = \frac{x - 1}{(x - 1)(x - 2)(x - 3)} \\ \\ = \frac{1}{(x - 2)(x - 3)}$