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AnnyKZ [126]
3 years ago
12

Plaskett's binary system consists of two stars that revolve in a circular orbit about a center of mass midway between them. This

statement implies that the masses of the two stars are equal (see figure below). Assume the orbital speed of each star is |v with arrow| = 160 km/s and the orbital period of each is 13.7 days. Find the mass M of each star. (For comparison, the mass of our Sun is 1.99 1030 kg.)
Physics
1 answer:
zepelin [54]3 years ago
6 0

Answer:

 M = 4.61 10³¹ kg

Explanation:

For this exercise we will use Newton's Second Law where the force is the gravitational outside

       F = ma

       G M₁ M₂ / r² = m a

The acceleration is centripetal

       a = v² / r’

Let's replace

The mass of the two stars in it, the distance between them is r and the distance around the center of mass is

       r’= r / 2

       G M² / r² = M v² / (r / 2)

       G M / r = 2 v²

The linear velocity module is constant, so we can use the kinematic relationship

       v = d / t

The distance of a circle of radius r ’is

      d = 2π r ’= 2π (r / 2)

      d = π r

We replace

      v = π r / T

Let's write the two equations

      v² = ½ G M / r

      v = π r / T

      r = v T /π

      v² = ½ G M π/ vT

      M = 2 v³ T / π G

Let's reduce the magnitudes to the SI system

     v = 160 Km / s = 1.60 10⁵ m / s

     T = 13.7 days (24 h / 1 day) (3600s / 1 h) = 1.18 10⁶ s

Let's calculate

     M = 2 (1.60 10⁵)³ 1.18 10⁶ / (π 6.67 10⁻¹¹)

     M = 4.61 10³¹ kg

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What total energy (in J) is stored in the capacitors in the figure below (C1 = 0.900 µF, C2 = 16.0 µF) if 1.80 10-4 J is stored
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The total energy  stored in the capacitors is determined as  2.41 x 10⁻⁴ J.

<h3>What is the potential difference of the circuit?</h3>

The potential difference of the circuit is calculated as follows;

U = ¹/₂CV²

where;

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  • V is the potential difference

For a parallel circuit the voltage in the circuit is always the same.

The energy stored in 2.5 μf capacitor is known, hence the potential difference of the circuit is calculated as follows;

U = ¹/₂CV²

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V = √2U/C

V = √(2 x 1.8 x 10⁻⁴ / 2.5 x 10⁻⁶)

V = 12 V

The equivalent capacitance of C1 and C2 is calculated as follows;

1/C = 1/C₁ + 1/C₂

1/C = (1)/(0.9 x 10⁻⁶)  +  (1)/(16 x 10⁻⁶)

1/C = 1,173,611.11

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C = 8.52 x 10⁻⁷ C

The total capacitance of the circuit is calculated as follows;

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The total energy of the circuit is calculated as follows;

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U =  ¹/₂(3.35 x 10⁻⁶ )(12)²

U = 2.41 x 10⁻⁴ J

Learn more about energy stored in a capacitor here: brainly.com/question/14811408

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Fix this problem please.
Vinil7 [7]

Answer:

In my knowledge....

Option E.........

Explanation:

I have no doubts it is option E 350N

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