Answer:
3.) 51.7 L
Explanation:
To find the volume, you need to use the Ideal Gas Law:
PV = nRT
In the equation,
-----> P = pressure (kPa)
-----> V = volume (L)
-----> n = moles
-----> R = Ideal Gas constant (8.314 kPa*L/mol*K)
-----> T = temperature (K)
First, you need to convert the temperature from Celsius to Kelvin. Then, you can plug the given values into the equation and simplify to find "V".
P = 68.0 kPa R = 8.314 kPa*L/mol*K
V = ? L T = 27.00 °C + 273 = 300 K
n = 1.41 moles
PV = nRT <----- Ideal Gas Law
(68.0 kPa)V = (1.41 moles)(8.314 kPa*L/mol*K)(300 K) <----- Insert values
(68.0 kPa)V = 3516.822 <----- Multiply right side
V = 51.7 <----- Divide both sides by 68.0
Answer:
The concentration of the unknown acid (HA) is 0.434M
The molar mass of HA is 13.3g/mole
Explanation:
DETERMINATION OF MOLARITY OF THE UNKNOWN ACID
CaVa/CbVb = Na/Nb
From the equation of reaction and at equivalence point, Na = Nb = 1
Therefore, CaVa = CbVb
Va (volume of acid solution) = 20mL = 20/1000 = 0.2L
Cb (concentration of KOH) = 0.715M
Vb (volume of KOH) = 12.15mL
Ca (concentration of acid) = CbVb/Va
Ca = 0.715M × 12.15mL/20mL = 0.434M
DETERMINATION OF MOLAR MASS OF HA
Number of moles of acid = concentration of acid × volume of acid solution in liters = 0.434 × 0.2 = 0.0868mole
Molar mass of HA = mass/number of moles = 1.153g/0.0868mole = 13.3g/mole
The one with the largest atomic radius is barium
Hoped this helped:)
Sodium/natrium is a metal from first column group so it should have one 1+ charge. Phosphate ion has 3- charge. That is why there 3 natrium ion for 1 phosphate ion when this molecule is dissolved in water. The ion formula would be:
(Na)
(PO
) ==> 3 Na
+ PO
