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3 years ago

7

The United States is a major producer of what element?

2 answers:

MAXImum [283]3 years ago

6 0

(copper) is correct on grad point

SVEN [57.7K]3 years ago

3 0

Answer:

Copper

Explanation:

In 2017, USA is fourth largest producer of copper in the whole world. The first three are Chile, China and Peru. Copper mining has been a major industry in USA since 1840s. In 2017 it produced 1.27 million metric tonne copper. Aluminum is another element produced in USA. In 2014, it was sixth largest Aluminum producer in the world.

Mercury has not been produced in USA since 1992. Although USA is a big consumer of diamonds, very few diamonds are produced here.

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Calculate the root means square velocity of nitrogen molecules in 25 degrees Celsius

Mademuasel [1]

Calculate the root mean square velocity of nitrogen molecules at 25°C.
297 m/s
149 m/s
515 m/s
729 m/s

7 0

3 years ago

ASAP PLZ HELP CHEMISTRY!!! CALCULATE THE MEAN AND THE UNCERTAINTY FOR EACH EXPERIMENT!!!

STALIN [3.7K]

Answer:

MEANS:

1 = 97.7

2 = 74.3

3 = 50

4 = 30

5 = 13

UNCERTAINTY:

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3 0

3 years ago

For a different reaction, the plot of the reciprocal of concentration versus time in seconds was linear with a slope of 0.056 M-

Bond [772]

Answer:

$C_t=0.165M$

Explanation:

From the question we are told that:

Slope $K=0.056 M-1 s -1$

initial Concentration $C_1=2.2M$

Time $t=100$

Generally the equation for Raw law is mathematically given by

$\frac{1}{C}_t=kt+\frac{1}{C}_0$

$\frac{1}{C}_t=0.056*100+\frac{1}{2.2}_0$

$C_t=0.165M$

4 0

3 years ago

A field worker is exposed to a xylene for a duration of 8 weeks at 40 hrs/wk. The concentration of xylene in the workplace is 40

Andrej [43]

Answer:

The chronic daily intake during the period of exposure is most nearly 0.012 mg/kg day.

Explanation:

Number of hours worker exposed to xylene = $40 hr/week\times 8 week = 320 hours$

The concentration of xylene in the workplace = $40 \mu g/m^3$

The worker is inhaling air at a rate of $0.9 m^3/hr$ .

Amount xylene inhaled by worker in an hour :

= $40\mu g/m^3\times 0.9 m^3/hr=36 \mu g/hr$

Amount xylene inhaled by worker in 320 hours:

$36 \mu g/hr\times 320 hr=11,520 \mu g=11,520\times 0.001 mg=11.520 mg$

1 μg = 0.001 mg

Amount xylene inhaled by worker in 320 hours = 11.520 mg

1 day = 24 hours

Amount xylene inhaled by worker in 1 day:

$\frac{24}{320}\times 11.520 mg=0.864 mg$

Assuming 70 kg body mass, the chronic daily intake of xylene :

$\frac{0.864 mg/day}{70 kg}=0.01234 mg/ kg day\approx 0.012 mg/ kg day$

The chronic daily intake during the period of exposure is most nearly 0.012 mg/kg day.

5 0

3 years ago

When 1.0g of diethyl ether is converted to vapor at its boiling point, about how much heat is absorbed? (C4H10O, Hvap= 15.7kj/mo

Aloiza [94]

Answer:

Option D = 0.2 Kj

Explanation:

Given data:

Mass of diethyl ether = 1.0 g

Hvap = 15.7 Kj / mol

Heat absorbed = ?

Solution:

Q = mass × Hvap / molar mass

Q = 1.0 g × 15.7 Kj / mol / 74.12 g/mol

Q = 15.7 Kj / 74.12

Q = 0.212 KJ

8 0

3 years ago