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FromTheMoon [43]
3 years ago
14

10. What two effects can the wrong pH have on an enzyme?

Chemistry
1 answer:
kow [346]3 years ago
5 0

Answer:

A pH environment has a significant effect on an enzymes. It can affect the intramolecular forces and change the enzyme's shape -- potentially to the point where it is rendered ineffective. With these effects in mind, typical enzymes have a pH range in which they perform optimally.

Explanation:

I hope this helps you.

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In breckenridge, colorado, the typical atmospheric pressure is 520. torr. what is the boiling point of water (hvap 40.7 kj/mol)
Art [367]
<span>362.51 Kelvin ln (p1/p2) =( dH / R) (1/T2 - 1/T1) ln (760 Torr /520Torr) =( 40,700 Joules / 8.314 J molâ’1K-1)(1/T2 - 1/373K) ln (1.4615) =( 4895.35)(1/T2 - 0.002681) 0.37946 = 4895.35/T2 - (0.002681)(4895.35) 0.37946 = 4895.35/T2 - (13.124) 0.37946 + 13.124 = 4895.35/T2 13.5039 = 4895.35/T2 T2 = 4895.35 / 13.5039 T2 = 362.51 answer is 362.51 Kelvin - 273 answer is also 89.5 Celsius</span>
4 0
3 years ago
2AgNO3 + CaCl2 → 2AgCl + Ca(NO3)2
Harrizon [31]

It can be found that 337.5 g of AgCl formed from 100 g of silver nitrate and 258.4 g of AgCl from 100 g of CaCl₂.

<u>Explanation:</u>

2AgNO₃ + CaCl₂ → 2 AgCl + Ca(NO₃)₂

We have to find the amount of AgCl formed from 100 g of Silver nitrate by writing the expression.

100 g \text { of } A g N O_{3} \times \frac{2 \text { mol } A g N O_{3}}{169.87 g A g N O_{3}} \times \frac{2 \text { mol } A g C l}{1 \text { mol } A g N O_{3}} \times \frac{143.32 g A g C l}{1 \text { mol } A g C l}

= 337.5 g AgCl

In the same way, we can find the amount of silver chloride produced from 100 g of Calcium chloride.

It can be found as 258.4 g of AgCl produced from 100 g of Calcium chloride.

4 0
3 years ago
1. Baking soda and vinegar combined *
Alina [70]

Answer:

dont know

Explanation:

4 0
3 years ago
Measurements show that unknown compound X has the following composition: element mass % carbon 41.0% hydrogen 4.58% oxygen 54.6%
anastassius [24]

Answer:

CHO

Explanation:

Carbon = 41%,  Hydrogen = 4.58%, oxygen = 54.6%

Step 1:

Divide through by their respective relative atomic masses

41/ 12,         4.58/1,         54.6/16

3.41              4.58            3.41

Step 2:

Divide by the lowest ratio:

3.41/3.41,      4.58/3.41,     3.41/3.41

1,                    1,                  1

Hence the empirical formula is CHO

8 0
3 years ago
Copper oxide is a: (Multiple Choice)
Triss [41]

Answer:

The answer is 5. Compound

7 0
3 years ago
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