Answer:
Elimination
Step-by-step explanation:
The following system of equations can be easily solved by elimination as we can simply eliminate x-term.
Substitution will take a lot of time because you need to move to make either x-term or y-term as the subject then substitute in.
Graphing Method — You need to find the intercepts of both equations. You also have to convert into slope-intercept form which takes a lot of time.
Answer:
The diameter of the target is
Step-by-step explanation:
we know that
In this problem the distance from the center of an archery target to the outside edge of the target is equal to the radius of the target
so
Remember that
The diameter is two times the radius
substitute
Answer:
<u>H</u><u>e</u><u>y</u><u> </u><u>M</u><u>a</u><u>t</u><u>e</u><u>!</u><u> </u><u>H</u><u>e</u><u>r</u><u>e</u><u>'</u><u>s</u><u> </u><u>y</u><u>o</u><u>u</u><u>r</u><u> </u><u>a</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u>.</u>
Step-by-step explanation:
<em><u>One packet of biscuits requires 2½ cups of flour = \frac{5}{2}25</u></em>
<em><u>One packet of biscuits requires 1 \times \frac{2}{3}1×32</u></em>
<em><u>One packet of biscuits requires 1 \times \frac{2}{3}1×32cups of sugar. = \frac{5}{3}35</u></em>
<em><u>Total ingradiants for one packet of biscuits =</u></em>
<em><u>Total ingradiants for one packet of biscuits =( \frac{5}{2} + \frac{5}{3} ) = \frac{15 + 10}{6} = \frac{25}{6}(25+35)=615+10=625</u></em>
<em><u>Then, total quantity of both ingredients used in 10 such packets of biscuits =</u></em>
<em><u>Then, total quantity of both ingredients used in 10 such packets of biscuits =10 \times ( \frac{25}{6} ) = 5 \times ( \frac{25}{3} ) = \frac{125}{3} = 41 \times \frac{2}{3}10×(625)=5×(325)=3125=41×32</u></em>
Hope it helped you!
A. is -5+10=5 so the answer to a is 5
b. is 49- (-14)=63 so the answer is 63
hope this helps:)
Step-by-step explanation:
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