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pshichka [43]
3 years ago
8

- (09.02)

Mathematics
1 answer:
sergeinik [125]3 years ago
4 0

Answer:

1/3

Step-by-step explanation:

The only way it could be less than 9 is if the second cube is either 1 or 2. The probability of either of those outcomes is 2/6, simplified to be 1/3

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Maverick spends 20 minutes of each day reading. Let d be the number of days that he reads, and let m represent the total minutes
MAVERICK [17]

Answer:

Assuming the question is to create an equation, it would be m = 20d

Step-by-step explanation:

5 0
2 years ago
Rewrite the following 7(3+5=___+___​
Ray Of Light [21]

Answer:

21+35

Step-by-step explanation:

use distributive property, multiply 7 by the two numbers in the parenthesis

keep the problem though.

6 0
3 years ago
The Office of Student Services at a large western state university maintains information on the study habits of its full-time st
Vera_Pavlovna [14]

Answer:

0.8254 = 82.54% probability that the mean of this sample is between 19.25 hours and 21.0 hours

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 20 hours, standard deviation of 6:

This means that \mu = 20, \sigma = 6

Sample of 150:

This means that n = 150, s = \frac{6}{\sqrt{150}}

What is the probability that the mean of this sample is between 19.25 hours and 21.0 hours?

This is the p-value of Z when X = 21 subtracted by the p-value of Z when X = 19.5. So

X = 21

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{21 - 20}{\frac{6}{\sqrt{150}}}

Z = 2.04

Z = 2.04 has a p-value of 0.9793

X = 19.5

Z = \frac{X - \mu}{s}

Z = \frac{19.5 - 20}{\frac{6}{\sqrt{150}}}

Z = -1.02

Z = -1.02 has a p-value of 0.1539

0.9793 - 0.1539 = 0.8254

0.8254 = 82.54% probability that the mean of this sample is between 19.25 hours and 21.0 hours

3 0
3 years ago
Part A: Larry earned $11 walking his neighbors' dogs on Saturday. He earned some extra money on Sunday doing the same thing. Wri
djyliett [7]
So for part a the answer with be 11/6
Why 6 because count the weeks that wil be 6 so Monday Tuesday Wednesday thursaday and Friday then comes Saturday
3 0
3 years ago
Read 2 more answers
The tuft bind strength of a synthetic material used to make carpets is known to have a mean of 100 lb and standard deviation of
emmasim [6.3K]

Answer:

The null hypothesis is: H_{0}: \mu = 100

The alternative hypothesis is: H_{a}: \mu > 100

Step-by-step explanation:

At the null hypothesis, we test if the mean is equal to a certain value.

At the alternate hypothesis, we test if the mean is less than, more than, or different from the value tested at the null hypothesis.

The tuft bind strength of a synthetic material used to make carpets is known to have a mean of 100 lb and standard deviation of 20 lb.

This means that the null hypothesis is: H_{0}: \mu = 100

Could it be that the average tuft strength is above 100 lb?

The world above means that the appropriate alternative hypothesis is: H_{a}: \mu > 100

3 0
3 years ago
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