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3 years ago

Tom and Jack spend a certain amount of money from their accounts each week at a pet shelter.

Mathematics

2 answers:

Alex3 years ago

5 0

Answer:

i did the test its c

Step-by-step explanation:

miv72 [106K]3 years ago

3 0

D) Function 2, because Jack spends $8 each week and Tom spends $7 each week

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Please help me I'm stuck on this question.

valentinak56 [21]

Its 1 and 9/7..............

7 0

3 years ago

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ASAP ASAP ASAP ASAP ILL SUBTO YOU IF YU ANSWER

UkoKoshka [18]

Answer:

Answer: B

Step-by-step explanation:

5 Inches × 6 Inches

4 0

3 years ago

Plant A: A graph has time (weeks) on the x-axis, and height (inches) on the y-axis. A line goes through points (0, 3), (1, 4.8),

butalik [34]

Answer:

The correct option is;

No, The greater rate of change of Plant A will result in it being 0.9 inches taller in 6 weeks

Step-by-step explanation:

The parameters given are;

Plant A:

Weeks, Height

0, 3

1, 4.8

2, 6.6

3, 8.4

The rate of change of height, H per week, t, $\left (\dfrac{dH}{dt} \right )$ for plant A per week is therefore;

$\dfrac{dH}{dt} = \dfrac{H_n - H_{(n-1)} }{t_n - t_{(n-1)}} = \dfrac{8.4 - 3 }{3 - 0} = \dfrac{5.4}{3} = 1.8 \ inches/week$

Therefore we have;

H = 1.8 × t + 3

At week 6,

H = 3 + 6×1.8 = 13.8 inches

Plant B

Weeks, Height

2, 7.3

3, 8.7

4, 10.1

The rate of change of height, H per week, t, $\left (\dfrac{dH}{dt} \right )$ for plant B per week is given as follows;

$\dfrac{dH}{dt} = \dfrac{H_n - H_{(n-1)} }{t_n - t_{(n-1)}} = \dfrac{10.1 - 7.3 }{4 - 2} = \dfrac{2.8}{2} = 1.4 \ inches/week$

Therefore we have;

When t = 2, H = 7.3 hence, 7.3 = 2 × 1.4 + H₀

Where:

H₀ = H at t = 0

H₀ = 7.3 - 2 × 1.4 = 4.5

At week 6 we have;

H = 4.5 + 6×1.4 = 12.9 inches

Which indicates that Plant A will be 0.9 inches taller than Plant B at week 6.

The correct option is therefore;

No, The greater rate of change of Plant A will result in it being 0.9 inches taller in 6 weeks.

5 0

3 years ago

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Can anyone help. Greatly appreciate:)

PilotLPTM [1.2K]

Answer:

Area= 12 units squared, Perimeter= 16.12899

Step-by-step explanation:

$AC= \sqrt{(4-0)^{2}+ (0+4)^{2}} = 4\sqrt{2}$

$AB= \sqrt{(0-4)^{2}+ (2-0)^{2} } = 2\sqrt{5}$

$BC= \sqrt{(0-0)^{2}+ (2+4)^{2} }= 6$

So, perimeter= $4\sqrt{2} + 2\sqrt{5} +6= 16.12899$

$Area= \frac{1}{2}bh\\$

$= \frac{1}{2}BC\sqrt{(4-0)^{2}+(0-0)^{2} }$

$= 12$ $units^{2}$

6 0

3 years ago

⦁ Determine if the equation represents a direct variation. .8x = 1.6y ⦁ Suppose y varies directly with x. Write a direction vari

Mkey [24]

Part A:

Given that

$0.8x=1.6y\Rightarrow x= \frac{1.6}{0.8} y=2y$

Thus, x = ky where k = 2.

Therefore, the given equation is a direct variation.

Part B:

If y varies directly as x, then y = kx.

Given that y = 5 when x = 2, then

$5=2k \\ \\ \Rightarrow k=\frac{5}{2} =2.5 \\ \\ \Rightarrow y=2.5x$

When x = 12, y = 2.5(12) = 30.

Part C:

If y varies directly as x, then y = kx.

Given that y = 9 when x = -6, then

$9=-6k \\ \\ \Rightarrow k=-\frac{9}{6} =-\frac{3}{2} \\ \\ \Rightarrow y=-\frac{3}{2}x$

It can be seen that the equation above satisfies all the rows of the given table, therefore, y varies with x for the data in the question and the equation for the direct variation is $y=-\frac{3}{2}x$

Part 4:

If y varies directly as x, then y = kx.

Given that y = 1 when x = -2, then

$1=-2k \\ \\ \Rightarrow k=-\frac{1}{2} \\ \\ \Rightarrow y=-\frac{1}{2}x$

It can be seen that the equation above does not satisfies the other rows of the given table, therefore, y does not vary with x for the data in the question.

8 0

3 years ago

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