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podryga [215]
3 years ago
6

Tom and Jack spend a certain amount of money from their accounts each week at a pet shelter.

Mathematics
2 answers:
Alex3 years ago
5 0

Answer:

i did the test its c

Step-by-step explanation:

miv72 [106K]3 years ago
3 0
D) Function 2, because Jack spends $8 each week and Tom spends $7 each week
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Find the measures of the missing angles
Oliga [24]

Answer:

Step-by-step explanation:

∠1 = 180° - 88° = 92°

∠5 = 81° (alternate interior angles)

∠4 = 180° - ( 81° + 64° ) = 35°

∠3 = 180° - ( 81° + 35° ) = 64°

∠2 = 88° - 64° = 24°

4 0
3 years ago
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Darlene kicks a soccer ball off the ground and in the air, with an initial velocity of 34 feet per second. using the formula h(t
monitta

Answer:

18.1 is the answer. I am glad I could help.



7 0
3 years ago
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Using the expression 10 x 2/5 as an example, describe how to multiply a whole number by a fraction that is less than one.
Schach [20]
To multiply a whole number by a fraction less than one, you have to rewrite the whole number in the expression as a fraction by putting a one under it.
For example, in 10 x 2/5, you would rewrite the 10 to 10/1 x 2/5.
Then, you would multiply the top and bottom of the two fractions. In this case, it would be 10 x 2 and 1x5. This would result in 20/5.
Finally, you would simplify this fraction by dividing. The final answer is 4.
5 0
2 years ago
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Solve the following equation on the interval [0, 2π). tan^2x sin x = tan^2x
Alenkasestr [34]
<h3>Given</h3>

tan(x)²·sin(x) = tan(x)²

<h3>Find</h3>

x on the interval [0, 2π)

<h3>Solution</h3>

Subtract the right side and factor. Then make use of the zero-product rule.

... tan(x)²·sin(x) -tan(x)² = 0

... tan(x)²·(sin(x) -1) = 0

This is an indeterminate form at x = π/2 and undefined at x = 3π/2. We can resolve the indeterminate form by using an identity for tan(x)²:

... tan(x)² = sin(x)²/cos(x)² = sin(x)²/(1 -sin(x)²)

Then our equation becomes

... sin(x)²·(sin(x) -1)/((1 -sin(x))(1 +sin(x))) = 0

... -sin(x)²/(1 +sin(x)) = 0

Now, we know the only solutions are found where sin(x) = 0, at ...

... x ∈ {0, π}

8 0
3 years ago
Write the first five terms of the sequence. an=n2 +2​
Alla [95]

Answer:

The first five terms of the given sequence

3, 6, 11, 18, 27

Step-by-step explanation:

It is given that,

an=n² +2​

<u>To find the first five terms</u>

a₁ = 1² + 2 = 1 + 2 = 3

a₂ = 2² + 2 = 4 + 2 = 6

a₃ = 3² + 2 = 9 + 2 = 11

a₄ = 4² + 2 = 16 + 8 = 18

a₅ = 5² + 2 = 25 + 2 = 27

Therefore the first five terms of the given sequence

3, 6, 11, 18, 27

4 0
3 years ago
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