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-BARSIC- [3]
3 years ago
15

So teacher asked her to find 42.6÷10 to the second power how many places in what direction should sue move the decimal point to

get the correct quotient
Mathematics
1 answer:
ki77a [65]3 years ago
4 0

move the decimal point 2 places to the left

42.6 / 10^{2} = 0.426


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Evaluate the expression 3.14(a2 + ab) when a = 3 and b = 4. (Input decimals only, such as 12.71, as the answer.)
soldier1979 [14.2K]
A= 3
b= 4

=3.14(a^2 + ab)
substitute the given a & b values in expression

=3.14((3)^2 + (3*4))
multiply inside parentheses

=3.14(9 + 12)
add inside parentheses

=3.14(21)
multiply

=65.94


ANSWER: 65.94

Hope this helps! :)
8 0
3 years ago
Write an equation of the line containing the point (3,5) and perpendicular to the line 4x-3y=5
ICE Princess25 [194]

Answer:

Step-by-step explanation:

In order to write the equation of the line perpendicular to the given line, we first have to know what the slope of the given line is, and there's no way to tell by looking at it in its current form, which is standard. We need to solve that equation for y to determine the slope of that line. Solving for y:

-3y=-4x+5 and

3y = 4x - 5 (just change all the signs so our y term isn't negative anymore...yes, you're "allowed" to do that!) and

y=\frac{4}{3}x-\frac{5}{3} So we can see now that the slope of this line is 4/3. That means that the perpendicular slope is -3/4. Passing through the given point (3, 5):

y-5=-\frac{3}{4}(x-3)* and

y-5=-\frac{3}{4}x+\frac{9}{4} and

y=-\frac{3}{4}x+\frac{9}{4}+\frac{20}{4} so

y=-\frac{3}{4}x+\frac{29}{4}** and, in standard form:

4y = -3x + 29 and

3x + 4y = 29***

* : point-slope form

** : slope-intercept form

*** : standard form

3 0
3 years ago
Please need help with one
natulia [17]

the answer of m angle q is 77

7 0
3 years ago
Find an equation in standard form for the hyperbola with vertices at (0, ±9) and foci at (0, ±11)
Katen [24]

Answer:

\frac{y^{2} }{81} -\frac{x^{2} }{40} }=1 is standard equation of hyperbola with vertices at (0, ±9) and foci at (0, ±11).

Step-by-step explanation:

We have given the vertices at (0, ±9) and foci at (0, ±11).

Let (0,±a)  = (0,±9) and (0,±c)  = (0,±11)

The standard equation of parabola is:

\frac{y^{2} }{a^{2} } -\frac{x^{2} }{b^{2} }=1

From statement, a  = 9

c² = a²+b²

(11)²  = (9)²+b²

121-81  = b²

40  = b²

Putting the value of a² and b² in standard equation of parabola, we have

\frac{y^{2} }{81} -\frac{x^{2} }{40} }=1 which is the answer.

3 0
3 years ago
12c+2d=48g solve for d
Lostsunrise [7]

Answer:

d=−6c+24g

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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