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kicyunya [14]
3 years ago
12

Mr. Abbot buys eight boxes of granola bars for a party each box has nine granola bars after the parties there are 39 bars left h

ow many bars were eating during the party
Mathematics
1 answer:
Fittoniya [83]3 years ago
7 0

Answer:

no of box multiply by no of granolas then subtract 39 bars

8×9=72

72-39=33

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Which of the following statements does not describe the structure of an atom?
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Answer:

B) Inside the nucleus of an atom are protons and electrons.

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2 years ago
Find the errors and correct the following mathematical sentences.​
zhuklara [117]

Answer:

The correct answers are:

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=x^2 +14x +49

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6 0
3 years ago
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Use Simpson's Rule with n = 10 to approximate the area of the surface obtained by rotating the curve about the x-axis. Compare y
DiKsa [7]

The area of the surface is given exactly by the integral,

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y(x)=\dfrac15x^5\implies y'(x)=x^4

so the area is

\displaystyle\pi\int_0^5\sqrt{1+x^8}\,\mathrm dx

We split up the domain of integration into 10 subintervals,

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where the left and right endpoints for the i-th subinterval are, respectively,

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with midpoint

m_i=\dfrac{\ell_i+r_i}2=\dfrac{2i-1}4

with 1\le i\le10.

Over each subinterval, we interpolate f(x)=\sqrt{1+x^8} with the quadratic polynomial,

p_i(x)=f(\ell_i)\dfrac{(x-m_i)(x-r_i)}{(\ell_i-m_i)(\ell_i-r_i)}+f(m_i)\dfrac{(x-\ell_i)(x-r_i)}{(m_i-\ell_i)(m_i-r_i)}+f(r_i)\dfrac{(x-\ell_i)(x-m_i)}{(r_i-\ell_i)(r_i-m_i)}

Then

\displaystyle\int_0^5f(x)\,\mathrm dx\approx\sum_{i=1}^{10}\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx

It turns out that the latter integral reduces significantly to

\displaystyle\int_0^5f(x)\,\mathrm dx\approx\frac56\left(f(0)+4f\left(\frac{0+5}2\right)+f(5)\right)=\frac56\left(1+\sqrt{390,626}+\dfrac{\sqrt{390,881}}4\right)

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