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Sauron [17]
3 years ago
14

PLEASE help. The problem is to find the indicated sum.​

Mathematics
1 answer:
alukav5142 [94]3 years ago
8 0
The indicated sum is 350. The answer is 350 because the E or sigma is making you do (6j+2) ten times. Every time you do 6j+2 you start with j as 1 and add a 1 to j for every time you add. For example, [6(1)+2]+[6(2)+2]+[6(3)+2]...[6(10)+2].

Hope this helps.
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The endpoints of the diameter of a circle are (−2, −3) and (4, −1). Which equation represents the circle?
Alika [10]

Answer:

The equation of circle is (x-1)^{2}+(y-2)^{2} = 18

Step-by-step explanation:

Given the endpoints of the diameter of a circle: (-2,-3) and (4,-1)

We know that the equation of circle is

(x-h)^{2} + (y-k)^{2}= r^{2}

where (x,y) is any point on the circle, (h,k) is center of the circle and r is radius of circle.

To find (h,k): the center is midpoint of diameter

Midpoint of diameter with end points (x1,y1) and (x2,y2) is given by

(  \frac{x1+x2}{2} , \frac{y1+y2}{2}  )

( \frac{-2+4}{2} , \frac{-3-1}{2}  )

(1,2)

Hence (h,k) is (1,2)

Substituting values of (h.k) and (x.y) as (1,2) and (4,-1) respectively in equation of circle, we get

(4-1)^{2} +(-1-2)^{2} = r^{2}

r^{2} = 18

Now substituting values of (h,k) and r^{2} in equation of circle, we get

(x-1)^{2}+(y-2)^{2} = 18

Hence the equation of circle is (x-1)^{2}+(y-2)^{2} = 18

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Answer:

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Step-by-step explanation:

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step5:6(x+3)>12

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Answer:

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