Answer:
“I really love the design work in engineering, the face-to-face interaction with clients, and the opportunity to see projects come to life. But if I had to pick one thing that I don’t enjoy as much, I would have to say it’s contract preparation.”
Answer:
The weather conditions do not suggest a blizzard. It is explained below.
Explanation:
wind_speed=randi([12 56],24,1);
visibility=randi([1 10],24,1)/10;
storm_data=[wind_speed,visibility];
save stormtrack.dat storm_data -ascii
clear
load stormtrack.dat
fprintf('Below is the storm data from the file stormtrack.dat \n');
disp(stormtrack)
wind_speed=stormtrack(:,1);
visibility=stormtrack(:,2);
L=length(wind_speed);
count=0;
i=0;
while count<4 && i<L
i=i+1;
if wind_speed(i)>=30 && visibility(i)<=0.5
count=count+1;
else
count=0;
end
end
if count==4
fprintf('The weather conditions suggest a blizzard.\n')
else
fprintf('The weather conditions do not suggest a blizzard.\n')
end
Results:
Below is the storm data from the file stormtrack.dat
49.0000 0.1000
56.0000 0.4000
44.0000 0.6000
27.0000 0.7000
38.0000 0.5000
16.0000 0.9000
52.0000 0.8000
1 51.0000 1.0000
48.0000 0.6000
23.0000 0.4000
38.0000 0.2000
13.0000 0.7000
31.0000 0.8000
26.0000 0.5000
19.0000 0.1000
20.0000 0.3000
31.0000 0.2000
16.0000 0.3000
38.0000 0.5000
33.0000 0.6000
43.0000 0.5000
43.0000 0.9000
40.0000 0.6000
13.0000 1.0000
The weather conditions do not suggest a blizzard.
Answer:
I would like to help can you take a picture without the bot telling you something. Maybe then I can figure it out.
Complete Question:
A metal plate of 400 mm in length, 200mm in width and 30 mm in depth is to be machined by orthogonal cutting using a tool of width 5mm and a depth of cut of 0.5 mm. Estimate the minimum time required to reduce the depth of the plate by 20 mm if the tool moves at 400 mm per second.
Answer:
26 mins 40 secs
Explanation:
Reduction in depth, Δd = 20 mm
Depth of cut, 
Number of passes necessary for this reduction, 
n = 20/0.5
n = 40 passes
Tool width, w = 5 mm
Width of metal plate, W = 200 mm
For a reduction in the depth per pass, tool will travel W/w = 200/5 = 40 times
Speed of tool, v = 100 mm/s
minimum time required to reduce the depth of the plate by 20 mm:
number of passes * Time/pass
n * Time/pass
40 * 40
1600 = 26 mins 40 secs
