Answer:

Explanation:
From the question we are told that:
Thickness 
Internal Pressure
Shear stress 
Elastic modulus 
Generally the equation for shear stress is mathematically given by
  
Where
r_i=internal Radius
Therefore
  
  
Generally
  
  
  
Generally the equation for outer diameter is mathematically given by
  
  
Therefore
Assuming that the thin cylinder is subjected to integral Pressure 
Outer Diameter is
  
 
        
             
        
        
        
so people dont die whaddya think?
 
        
                    
             
        
        
        
Answer:
1) The absolute pressure equals = 96.98 kPa
2) Absolute pressure in terms of column of mercury equals 727 mmHg.
Explanation:
using the equation of pressure statics we have

Now since it is given that at 6400 meters pressure equals 45 kPa absolute hence from equation 'i' we obtain

Applying values we get


Now the pressure in terms of head of mercury is given by

Applying values we get

 
        
             
        
        
        
Answer:
 Temperature distribution is 
Heat flux=q
Heat rate=q A   
Explanation:
We know that for no heat generation and at steady state



a and are the constant.
Given that heat flux=q
We know that heat flux given as 

From above we can say that 

Alos given that when x= L temperature is T(L)=T


So temperature T(x)


So temperature distribution is 
Heat flux=q
Heat rate=q A          (where A is the cross sectional area of wall)