Gordon Gould has been forced to fight for his claim to the invention of the laser because:_________.a. he was forced out of the
1 answer:
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Answer:
a) the expected flow rate is 31.4 ft³/s
b) the required brake horsepower is 2808.4 bhp
c) the location of pump inlet to avoid cavitation is -8.4 ft
Explanation:
Given the data in the question;
free surface elevation = 200 ft
total length of pipe required = 1000 ft
diameter = 12 inch
Iron with relative roughness ( k/D ) = 0.0005
H = 665-0.051Q² [Qinft ]
a) the expected flow rate
given that;
k/D = 0.0005
k/2R = 0.0005
R/k = 1000
now, we determine the friction factor;
1/√f = 2log₁₀( R/k ) + 1.74
we substitute
1/√f = 2log₁₀( 1000 ) + 1.74
1/√f = 6 + 1.74
1/√f = 7.74
√f = 1/7.74
√f = 0.1291989
f = (0.1291989)²
f = 0.01669
Now, Using Bernoulli theorem between two reservoirs;
(p/ρq)₁ + (v²/2g)₁ + z₁ + H = (p/ρq)₂ + (v²/2g)₂ + z₂ + h
so
0 + 0 + 0 + 665-0.051Q² = 0 + 0 + 200 + flQ²/2gdA²
665-0.051Q² = 200 + flQ²/2gdA²
665-0.051Q² = 200 +[ ( 0.01669 × 1000 × Q² ) / (2 × 32.2 × (π/4)² × 1⁵ )
665 - 0.051Q² = 200 + [ 16.69Q² / 39.725 ]
665 - 200 - 0.051Q² = 0.420138Q²
665 - 200 = 0.420138Q² + 0.051Q²
465 = 0.471138Q²
Q² = 465 / 0.471138
Q² = 986.97196
Q = √986.97196
Q = 31.4 ft³/s
Therefore, the expected flow rate is 31.4 ft³/s
b) the brake horsepower required to drive the pump (assume an efficiency of 78%).
we know that;
P = ρgHQ / η
where; H = 665 - 0.051(986.97196) = 614.7
we substitute;
P = ( 62.42 × 614.7 × 31.4 ) / ( 0.78 × 550 )
P = 1204804.6236 / 429
P = 2808.4 bhp
Therefore, the required brake horsepower is 2808.4 bhp
c) the location of pump inlet to avoid cavitation (assume the required NPSH=25 ft).
NPSH = ( / ρg) - h
- ( P
/ ρg )
we substitute
25 = ( 2116 / 62.42 ) - h - ( 30 / 62.42 )
h = 8.4 ft
Therefore, the location of pump inlet to avoid cavitation is -8.4 ft
Answer:
Check the explanation
Explanation:
Main1.java
import java.lang.InterruptedException;
import java.lang.Thread;
import java.util.Random;
public class Main {
final private static int FARMERS = 10;
public static void main(String[] args) {
Bridge bridge = new Bridge();
Random r = new Random();
System.out.println("Running with " + FARMERS + " farmers...");
// Enter a bunch of farmers from different directions.
for (int i = 0; i < FARMERS; i++) {
Farmer farmer;
if (r.nextBoolean()) {
farmer = new SouthBoundFarmer(bridge);
} else {
farmer = new NorthBoundFarmer(bridge);
}
cross(farmer);
}
}
private static void cross(Farmer f) {
new Thread(f).start();
}
}
SouthBoundFarmer.java
public class SouthBoundFarmer extends Farmer {
public SouthBoundFarmer(Bridge b) {
super(b);
this.name = "South";
}
}
Farmer.java
import java.lang.InterruptedException;
import java.util.Random;
public class Farmer implements Runnable {
private Bridge bridge;
private Random random;
protected String name;
public Farmer(Bridge b) {
this.bridge = b;
this.random = new Random();
}
public void crossBridge(Bridge bridge) {
System.out.println("[" + this.name + "] Waiting to enter bridge...");
try {
bridge.enter();
System.out.println("[" + this.name + "] Entering bridge...");
// Crossing bridge...some farmers are fast, others are slow :P
Thread.sleep(1000 + random.nextInt(9000));
System.out.println("[" + this.name + "] Leaving bridge...");
} catch (InterruptedException e) {
System.out.println("...Interrupted!");
} finally {
bridge.leave();
}
}
public void run() {
this.crossBridge(this.bridge);
}
}
Bridge.java
import java.lang.InterruptedException;
import java.util.concurrent.Semaphore;
public class Bridge {
private Semaphore lock;
public Bridge() {
this.lock = new Semaphore(1);
}
public void enter() throws InterruptedException {
this.lock.acquire();
}
public void leave() {
this.lock.release();
}
}
NorthBoundFarmer.java
public class NorthBoundFarmer extends Farmer {
public NorthBoundFarmer(Bridge b) {
super(b);
this.name = "North";
}
}
KINDLY CHECK THE OUTPUT BELOW :
