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natta225 [31]
3 years ago
10

Based on its location on the periodic table which element would be most likely to form a negative ion

Physics
2 answers:
Vinvika [58]3 years ago
8 0

Answer:

This question is incomplete but the completed question is below

Based on its location on the periodic table, which element would be most likely to form a negative ion?

A. Aluminum (Al)

B. Copper (Cu)

C. Sodium (Na)

D. Fluorine (F)

The correct option is D

Explanation:

An atom will become negatively charged when it accepts/gains electron(s). Atoms lose/gain electrons in order to achieve there octet configuration. In the periodic table, metals donate/lose their valence electron(s) to become positively charged (cation) while non-metals accept/gain electron(s) to become negatively charged (anion).

From the explanation above, it can be deduced that aluminium (Al) will lose the three valence electrons in it's outermost shell to become Al³⁺, copper (Cu) will lose two valence electrons to become Cu²⁺ while sodium (Na) will lose the only electron it has on its outermost shell to become Na⁺.

Fluorine (F), a non-metal, however gains an electron to become a negatively charged ion (F⁻).

blagie [28]3 years ago
6 0

Answer:

Since Fluorine is very electronegative, it can easily absorb the electrons of other elements. Since it sucks up electron, this gives Fluorine an excess electron thus making it a negative ion F-.

Explanation:

because it is

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Answer:

Total displacement will be 47 meter

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We have given that first the student go eastward towards bus stop 20 meters

But he realizes that she dropped his physics notebook and so h=she turns back along the same way up to 18 meters

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And he travel 45 meters in east along the bus stop so total displacement = 45+2 = 47 meters

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3 years ago
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PART A)

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3, A 4kg block is pushed 2m at an acceleration of 0.2m/s square up a vertical wall by a constant force F applied at an angle of
Andrews [41]

The work done by the applied force on the block against the frictional force is 15.75 J.

<h3>Work done by the applied force</h3>

The work done by the applied force is calculated as follows;

W = Fd

F - Ff = ma

where;

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Fcos(37) - μmgsin(37) = ma

Fcos(37) - (0.3)(4)(9.8)sin(37) = 4(0.2)

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W = Fdcosθ

W = 9.86 x 2 x cos(37)

W = 15.75 J

Thus, the work done by the applied force on the block against the frictional force is 15.75 J.

Learn more about work done here: brainly.com/question/25573309

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2 years ago
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