Antoinette was diagnosed with hypertension, a noncommunicable disease in which her blood pressure is higher than normal. What is
1 answer:
You might be interested in
Assume that the ball rolls to the right.
From the velocity-time graph, the acceleration is
a = (0 - 10 m/s)/(4 - 0 s) = -2.5 m/²
Part (a)
Because the mass of the ball is 25g or 0.025 kg, the force that the road exerts on the ball is
F = (0.025 kg)*(-2.5 m/s²) = -0.0625 N
The force is negative because it acts in opposition to the motion of the ball.
Answer: 0.0625 N to the left.
Part (b)
The direction of the force exerted by the road is to the left because it opposes the motion of the ball to the right.
Part (c)
The unit force is 1 N (Newton), with the dimension (kg-m)/s².
From the velocity-time graph, the acceleration is
a = (0 - 10 m/s)/(4 - 0 s) = -2.5 m/²
Part (a)
Because the mass of the ball is 25g or 0.025 kg, the force that the road exerts on the ball is
F = (0.025 kg)*(-2.5 m/s²) = -0.0625 N
The force is negative because it acts in opposition to the motion of the ball.
Answer: 0.0625 N to the left.
Part (b)
The direction of the force exerted by the road is to the left because it opposes the motion of the ball to the right.
Part (c)
The unit force is 1 N (Newton), with the dimension (kg-m)/s².
Answer:
The magnetic field at the center of a circular loop is .
Explanation:
Given that,
Radius = 4.0 cm
Current = 2.0 A
We need to calculate the magnetic field at the center of a circular loop
Using formula of magnetic field
Where, I = current
r = radius
Put the value into the formula
Hence, The magnetic field at the center of a circular loop is .
Answer:
V = 5.4 m/s
Explanation:
It is given that,
Let mass of the block, m = 10 kg
Spring constant of the spring, k = 2 kN/m = 2000 N/m
Speed of the block, v = 6 m/s
Compression in the spring, x = 15 cm = 0.15 m
Let V is the speed of the block moving at the instant the spring has been compressed 15 cm. It can be calculated using the conservation of energy of spring mass system.
V = 5.61 m/s
From the given options,
V = 5.4 m/s
Hence, this is the required solution.