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quester [9]
3 years ago
14

Two identical metal balls a and b are mounted on insulating rods. Ball a has a charge of +q/2 and ball b is initially uncharged.

Ten ball a touched ball b what is resulting charge of ball a
Physics
2 answers:
oksano4ka [1.4K]3 years ago
6 0

Answer:

Help me please?

Explanation:

Did you get the answer? I believe it’s either C. +q or D. 0

rodikova [14]3 years ago
5 0

Answer:

q_end = q / 4  

Explanation:

Since the balls are in insulating barrels, it has no charge exchange with the earth, so it maintains its initial charge.

 

When the ball a touches the ball b and since the two are metallic the charge is distributed over the entire surface, by separating the two spheres that are of the same radius, the load was distributed between the two,

           

              q_end = q₀ / 2

              q_end = (q / 2) / 2

              q_end = q / 4

This is the charge on each ball.

If we keep touching the balls nothing else happens because the charges are already equal in both.

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Which of the following factors will negatively impact the rate of diffusion of a molecule?
Maurinko [17]

Answer:

A low difference in the concentration of the molecule across the media

Explanation:

Diffusion is a type of passive transport where the molecules move in the influence of concentration gradient of diffusing molecules i.e. from the higher concentration region to the lower concentration region. There are some factors which affect the rate of diffusion, these are written below -

  1. Mass of diffusing molecule - lighter molecules diffuse faster and heavier one diffuse relatively slower.
  2. Concentration gradient - rate of diffusion is higher if the difference in concentration of the diffusing particles is larger in the two regions.
  3. Distance traveled - molecules diffuse faster if they need to travel little distance during diffusion.
  4. Temperature - rate of diffusion will be greater at higher temperatures because the movement of diffusing molecules gets increased.
  5. Solvent density - rate of diffusion tend to be lower if the solvent has higher density.

Looking at these factors we can conclude that the second statement in the question tells about a negative impact regarding the diffusion because due to low difference in concentration across the two media, the rate of diffusion will be lower.

3 0
3 years ago
Magnetic Energy density affected by area?​
Mademuasel [1]

Answer:

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4 0
3 years ago
A ball is released from a hot air balloon moving downward with a velocity of -10.0 meters/second and a height of 1,000 meters. H
Nikolay [14]
Here, ball is released... and it is in free fall means with zero initial velocity.

We know, s = ut + 1/2 at²
Here, s = 1000 m
u = 0
a = 10 m/s2

Substitute their values, 
1000 = 0 + 1/2 * 10 * t²
2000 = 10 * t²
t² = 2000 /10
t = √200
t = 14.14 s

In short, Your Answer would be 14.14 seconds

Hope this helps!
7 0
3 years ago
Read 2 more answers
An airplane wing is designed so that the speed of the air across the top of the wing is 255 m/s when the speed of the air below
grin007 [14]
<h2>Answer:442758.96N</h2>

Explanation:

This problem is solved using Bernoulli's equation.

Let P be the pressure at a point.

Let p be the density fluid at a point.

Let v be the velocity of fluid at a point.

Bernoulli's equation states that P+\frac{1}{2}pv^{2}+pgh=constant for all points.

Lets apply the equation of a point just above the wing and to point just below the wing.

Let p_{up} be the pressure of a point just above the wing.

Let p_{do} be the pressure of a point just below the wing.

Since the aeroplane wing is flat,the heights of both the points are same.

\frac{1}{2}(1.29)(255)^{2}+p_{up}= \frac{1}{2}(1.29)(199)^{2}+p_{do}

So,p_{up}-p_{do}=\frac{1}{2}\times 1.29\times (25424)=16398.48Pa

Force is given by the product of pressure difference and area.

Given that area is 27ms^{2}.

So,lifting force is 16398.48\times 27=442758.96N

6 0
4 years ago
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