A constant force of 8.0 N is exerted for 4.0 s on a 16-kg object initially at rest. The change in speed of this object will be:
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speed of the car at t = 10 s is given as 10 m/s
now at t = 30 s car comes to rest so v = 0
now in this velocity time graph we can say slope will show the acceleration of the car as we know that acceleration is rate of change in velocity
as we know that
now from above formula
So slope of the graph will represent the acceleration of car which is 0.5 m/s^2