All categories

3 years ago

If a nanometer is one billionth of a meter (0.000 000 00 1 m), how many nanometers are there in one meter?

Chemistry

1 answer:

Anit [1.1K]3 years ago

6 0

Answer:

One billion

Explanation:

A nanometer is a BILLIONTH of a meter which means it takes one billion to equal a meter

You might be interested in

Balance chemical equation Fe3O4 = Fe + CO2

m_a_m_a [10]

equation Fe3O4=Fe+CO2 is an impossible reaction

5 0

4 years ago

Arrhenius base definition

kompoz [17]

Arrhenius base is a substance that , when dissolved in an aqueous solution , increase the concentration of hydroxide (OH) ion in the solution

I hope that's help !

6 0

3 years ago

Yield for this reaction?<br> Reaction: N2(g) + 3 H2(g) → 2 NH3 (g)

andriy [413]

Answer:

Yes, yield.

Explanation:

N2(g) + 3 H2(g) → 2 NH3 (g) balanced equation

First, find limiting reactant:

Moles H2 = 1.83 g x 1 mole/2 g = 0.915 moles H2

Moles N2 = 9.84 g N2 x 1 mole/28 g = 0.351 moles N2

The mole ratio of H2: N2 is 3:1, so H2 is limiting (0.915 is less than 3 x 0.351)

Theoretical yield of NH3 = 0.915 mol H2 x 2 mol NH3/3 mol H2 = 0.61 moles NH3

6 0

3 years ago

You decided you want to make spaghetti for supper. You first light the gas stove because you need to cook the meat. When the mea

zloy xaker [14]

Answer:

Explanation:

Brainliest

7 0

4 years ago

Read 2 more answers

La masa de una olla es de 300g y contiene 90% de aluminio. Hallar el número de moles de aluminio de la olla. P.A.(Al= 27)

Neko [114]

Explanation:

The mass of a pot is 300g and contains 90% aluminum. Find the number of moles of aluminum in the pot. P.A. (Al = 27)

The mass of aluminum present in the pot is:

$300 g * 90/100\\=270 g$

Hence, in the given pot 270g Al is present.

$Number of moles of Al=\frac{given mass ofAl}{its molar mass}$

The gram atomic mass of Al -27 g/mol

Given the mass of Al is 270 g

Substitute these values in the above formula:

$Number of moles of Al=\frac{given mass ofAl}{its molar mass}\\=\frac{270 g}{27 g} \\=10.0 mol$

Answer is 10.0 mol of Al is present.

6 0

3 years ago