Answer:
22
Explanation:
The atomic number indicates the amount of protons, so it would be 22
Answer:
c) Hexagonal close packed
Explanation:
The fact that a material is crystalline, amorphous or semicrystalline defines some of its properties. For example, if a material had the option of being crystalline or amorphous, it would be observed that in the crystalline state the density of the material would be greater in the amorphous state. This is because because of the order that the atoms follow in the crystalline material, it is possible to place more atoms in the same physical volume. When there are more atoms there is more mass in the same volume so the density is higher than when the material is amorphous.
The different crystalline structures are the following:
Simple cubic structures: the unit cell is a common edge cube, with a defined network point in each of its vertices.
Cubic structure centered on the body: the unit cell is a cube with a common edge. It has a defined network point in each of its vertices and a defined network point in the geometric center of the cube. INCLUDES a)
Cubic structure centered on the face: the unit cell is a cube with a common edge. It has a defined network point in each of its vertices and a defined network point in the geometric center of each of its faces. INCLUDES b) and d)
<span> ester of Ethanol and Ethanoic Acid is Ethyl Ethanoate. </span>
<span><span><span><span><span><span><span><span>C</span></span></span><span><span><span>2</span></span></span></span><span><span><span><span>H</span></span></span><span><span><span>5</span></span></span></span><span><span>O</span></span><span><span>H</span></span><span><span>(</span></span><span><span>l</span></span><span><span>)</span></span><span><span>+</span></span><span><span>C</span></span><span><span><span><span>H</span></span></span><span><span><span>3</span></span></span></span><span><span>C</span></span><span><span>O</span></span><span><span>O</span></span><span><span>H</span></span><span><span>(</span></span><span><span>l</span></span><span><span>)</span></span><span><span><span><span><span><span><span><span><span>c</span></span><span><span>o</span></span><span><span>n</span></span><span><span>c</span></span><span><span>.</span></span><span><span><span><span>H</span></span></span><span><span><span>2</span></span></span></span><span><span>S</span></span><span><span><span><span>O</span></span></span><span><span><span>4</span></span></span></span><span><span><span><span>/</span></span></span></span><span><span>w</span></span><span><span>a</span></span><span><span>r</span></span><span><span>m</span></span></span></span><span /></span></span></span><span><span><span><span>−</span><span>−−−−−−−−−−</span><span>→</span></span></span></span></span></span><span><span>C</span></span><span><span><span><span>H</span></span></span><span><span><span>3</span></span></span></span><span><span>C</span></span><span><span>O</span></span><span><span>O</span></span><span><span>C</span></span><span><span><span><span>H</span></span></span><span><span><span>2</span></span></span></span><span><span>C</span></span><span><span><span><span>H</span></span></span><span><span><span>3</span></span></span></span><span><span>(</span></span><span><span>a</span></span><span><span>q</span></span><span><span>)</span></span><span><span>+</span></span><span><span><span><span>H</span></span></span><span><span><span>2</span></span></span></span><span><span>O</span></span><span><span>(</span></span><span><span>l</span></span><span><span>)</span></span></span></span><span>C2H5OH(l)+CH3COOH(l)→conc.H2SO4/warmCH3COOCH2CH3(aq)+H2O(l)</span></span></span>
<span><span><span><span><span><span>Condition: Warm con. reactants with conc.</span></span></span></span><span>Condition: Warm con. reactants with conc.</span></span></span><span><span><span><span><span><span><span><span>H</span></span></span><span><span><span>2</span></span></span></span><span><span>S</span></span><span><span><span><span>O</span></span></span><span><span><span>4</span></span></span></span></span></span><span>H2SO4</span></span></span>
Answer:
e−(Ea/RT): the fraction of the molecules present in a gas which have energies equal to or in excess of activation energy at a particular temperature
