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Ivanshal [37]
3 years ago
11

About 8% of the U.S. population catches the flu each season. Assuming everyone has equal probability of catching the flu, about

what are the odds of catching the flu in a given season?
Mathematics
1 answer:
avanturin [10]3 years ago
8 0

Answer:

  • <u>The odds are 2 : 23, or about 0.09 :  1 (0.09 to 1).</u>

Explanation:

The <em>odds </em>of an event is the ratio of occurrence to non-occurrence of the event.

When you know the <em>probability</em> of an event, then you can calculate the odds by dividing the probability of occurence by the probability of non-occurrence.

Calling p the probability that an event will happen, 1 - p is the probability that it will not happen and the odds will be:

  • Odds = p / ( 1 - p)

You have p = 8% = 0.08, and 1 - p = 1 -0.08 = 0.92.

Therefore:

  • Odds = 0.08 / 0.92 = 8 : 92 = 2 : 23 ≈ 0.09 : 1 (0.09 to 1)

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Answer:

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Step-by-step explanation:

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Bruce drew a scale drawing of a restaurant. The scale he used was 1 millimeter 10 meters The restaurant's kitchen is 3 millimete
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Given that r = ( 7, 3, 9) and v = ( 3, 7, -9), evaluate r + v
uysha [10]

Answer:

b. (10,10,0)

Step-by-step explanation:

r+v can be evaluated if the vectors/matrices have the same dimensions.

These do. They are both 1 by 3 vectors.

Just add first to first in each.

Just add second to second in each.

Just add third to third in each.

Example:

(5,-5,6)+(1,2,3)

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Done!

In general, (a,b,c)+(r,s,t)=(a+r,b+s,c+t).

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