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Ivanshal [37]
3 years ago
11

About 8% of the U.S. population catches the flu each season. Assuming everyone has equal probability of catching the flu, about

what are the odds of catching the flu in a given season?
Mathematics
1 answer:
avanturin [10]3 years ago
8 0

Answer:

  • <u>The odds are 2 : 23, or about 0.09 :  1 (0.09 to 1).</u>

Explanation:

The <em>odds </em>of an event is the ratio of occurrence to non-occurrence of the event.

When you know the <em>probability</em> of an event, then you can calculate the odds by dividing the probability of occurence by the probability of non-occurrence.

Calling p the probability that an event will happen, 1 - p is the probability that it will not happen and the odds will be:

  • Odds = p / ( 1 - p)

You have p = 8% = 0.08, and 1 - p = 1 -0.08 = 0.92.

Therefore:

  • Odds = 0.08 / 0.92 = 8 : 92 = 2 : 23 ≈ 0.09 : 1 (0.09 to 1)

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12=3/4 y, what is y?
lesya692 [45]
..........................................

7 0
3 years ago
If it takes (a) men (b) hours to dig (c) holes, how many men are required to dig b holes in c hours?
docker41 [41]
Well, let's see . . .

You said that  (a) men can dig (c) holes in (b) hours.

So . . . It takes  (a) men  (b / c) hours to dig one hole.

And . . . It takes    One man  (a b / c) hours to dig one hole.

Now . . .  There are  (b) holes to be dug.

              It would take one man  (a b / c)·(b) = (a b² / c) hours to dig them all.

              But if you had 'x' men, it would only take them  (c) hours to do it.

So          c  =  (a b² / c)  /  x

           x c  =  (a b² / c)

           x     =  a b² / c²  men   . 

Now, I lost the big overview while I was doing that,
and just started following my nose through the fog.
So I have to admit that I'm not that confident in the answer.
But gosh durn it.  That's the answer I got, and I'm stickin to it.
Rrarrup !  
8 0
3 years ago
Find the x- and y-intercepts for the linear equation –3x + 4y = 24.
Sav [38]

Answer:

x- intercept = - 8, y- intercept = 6

Step-by-step explanation:

To find the x- intercept let y = 0 and solve for x

- 3x + 4(0) = 24

- 3x = 24 ( divide both sides by - 3 )

x = - 8 ← x- intercept

To find the y- intercept let x = 0 and solve for y

- 3(0) + 4y = 24

4y = 24 ( divide both sides by 4 )

y = 6 ← y- intercept

3 0
3 years ago
Does anyone know how to do this ?
goldenfox [79]

Answer: D) 32

Step-by-step explanation:

The area of a parallelogram equals its base times its height. Substitute the base and area into this formula to solve for the height:

A=bh

40=(5)(h)

h=8

If ABCD is a parallelogram, opposite sides are parallel, so AB is parallel to DC. If AB is parallel to DC, EB is parallel to DC. Since EB is parallel to DC, quadrilateral EBCD has at least one pair of parallel sides, making it a trapezoid. The area of a trapezoid is equal to \frac{h(b_{1}+b_{2})  }{2} where h is the height, b_{1} is one base, and b_{2} is the other base. Plug the necessary values into the formula:

A=\frac{h(b_{1}+b_{2})  }{2}

b_{1} =AB-AE\\DC=AB\\b_{1} =DC-AE\\b_{1} =5-2\\b_{1} =3

b_{2} =5

h=8

A=\frac{8(3+5)}{2}

A=32

The answer is D) 32.

6 0
3 years ago
The taxi and takeoff time for commercial jets is a random variable x with a mean of 8.4 minutes and a standard deviation of 3.5
Lorico [155]

Answer:

0.6672 is the required probability.            

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 8.4 minutes

Standard Deviation, σ = 3.5 minutes

We are given that the distribution of distribution of taxi and takeoff times is a bell shaped distribution that is a normal distribution.

According to central limit theorem the sum measurement of n is normal with mean \mu and standard deviation \sigma\sqrt{n}

Sample size, n = 37

Standard Deviation =

=\sigma\times \sqrt{n} = 3.5\times \sqrt{37}=21.28

P(taxi and takeoff time will be less than 320 minutes)

P( \sum x < 320) = P( z < \displaystyle\frac{320 - 37(8.4)}{21.28}) = P(z < 0.4323)

Calculation the value from standard normal z table, we have,  

P(\sum x < 320) =0.6672 = 66.72\%

0.6672 is the probability  that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

7 0
3 years ago
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