B is the answer to your question! hope I helped!!!
Answer:
The intense and constant activity of insulin synthesis explains why pancreatic beta cells possess more rough endoplasmic reticulum and ribosomes than other cells.
Explanation:
Both ribosomes and the rough endoplasmic reticulum are necessary for protein synthesis to occur. In cells whose function is to produce substances, such as glands, the content of these cellular structures is higher in order to fulfill their function.
The pancreatic beta cells, located in the islets of Langerhans, have the function of synthesizing insulin, an endocrine hormone in charge of regulating the glucose content in the blood. <u>Because the beta cells constantly produce insulin, their content of rugged endoplasmic reticulum and ribosomes is high, in order to satisfy the demand for this hormone in the body</u>.
A healthy lifestyle that includes adequate rest, exercise, and a balanced diet.
Type I is insulin-dependent; Type II is non-insulin-dependent. Type I requires injectable insulin to treat; Type II can be treated without insulin with correct diet and exercise. A person is usually born with Type I diabetes, whereas Type II has been linked to obesity and poor dietary habits.90 calories; one fat exchange = 45 calories.
Exchange lists can be used by diabetics to give freedom of choice in what they can have to eat or drink. It allows diabetics to select types and amounts of foods while maintaining a healthy calorie level.30 grams or 2 carbs, because two slices of bread 2 starch servings.
Carbohydrate counting can help people control their carbohydrate intake, which helps control blood sugar. It allows flexibility in menu planning because no food is excluded, and only carbohydrates are counted.
Answer:
ΔG'° for the coupled reaction = -16.7 kJ/mol
<em>Note: The question is missing some parts. The complete question is as follows:</em>
<em>The first reaction in glycolysis is the phosphorylation of glucose:
</em>
<em>
Pi+glucose⟶glucose−6−phosphate+H2O
</em>
<em>This is a thermodynamically unfavorable process, with ΔG∘′= +13.8kJ/mol. In a liver cell at 37 ∘C the concentrations of both phosphate and glucose are normally maintained at about 5 mM each.</em>
<em>This very low concentration of the desired product would be unfavorable for glycolysis. In fact the reaction is coupled to ATP hydrolysis to give the overall reaction: ATP + glucose → glucose-6-phosphate + ADP + H+</em>
<em>What is the ΔG'° for the coupled reaction?</em>
Explanation:
The coupling of ATP hydrolysis which is a thermodynamically favourable reaction to the phosphorylation of glucose makes it favourable. Since the two reactions constitute a sequential reaction, their standard free energy changes are additive.
For ATP hydrolysis: ATP + H₂O ---> ADP + Pi ; ΔG'° = -30.5KJ/mol
For phosphorylation of glucose: Pi + glucose⟶glucose−6−phosphate + H2O ; ΔG'° = +13.8 kJ/Mol
For the overall reaction: ATP + glucose → glucose-6-phosphate + ADP + H⁺ ; ΔG'° = 13.8 + (-30.5) kJ/mol = -16.7 kJ/mol
Therefore, ΔG'° for the coupled reaction = -16.7 kJ/mol
