The given compound 1-bromo-1-chlorobutane is an optically active compound .
Because this compound does not have plane of symmetry (POS) and center of symmetry (COS) i.e. does not have di-symmetry . And also forms non superimposable mirror image . the compound is optically active .
It has chiral center.
Here , the chiral carbon is bonded to 4 distinct groups such as : chlorine , bromine , hydrogen and propyl .
<h3>What is di-symmetry?</h3>
Di-symmetry is that which have no center of symmetry and plane of symmetry and alternate axis of symmetry .
<h3>Chiral center :</h3>
Have Sp3 hybridized center (4sigma bond ) .
4 distinct group is attached to the chiral atom. form non -superimposable mirror image .
<h3>What is optical isomerism ?</h3>
Same molecular formula and same structural formula . also have same physical and chemical properties .
They differ in their behavior towards plane polarized light (ppl) .
Learn more about chiral center here:
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Answer:
801 •C
Explanation:
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Answer:
Hi, Friend!
My Answer would be Number 3 Frequency
Explanation:
Frequency describes the number of waves that pass a fixed place in a given amount of time.
<h3>
Answer:</h3>
3.38 × 10²⁴ molecules CO₂
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[Given] 5.61 moles CO₂
[Solve] molecules CO₂
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
- [DA] Set up:
- [DA] Multiply/Divide [Cancel out units]:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
3.37834 × 10²⁴ molecules CO₂ ≈ 3.38 × 10²⁴ molecules CO₂
Answer:
1.88 x 10²³molecules of H₂O
Explanation:
Given parameters:
Mass of H₂O = 5.609g
Unknown:
Number of molecules of H₂O = ?
Solution:
To solve this problem, we need to find the number of moles of given compound first.
Number of moles = 
Molar mass of H₂O = 2(1) + 16 = 18g/mol
Number of moles = 
= 0.31mole
From mole concept;
1 mole of a substance contains 6.02 x 10²³molecules
0.31 mole of H₂O will therefore contain 0.31 x 6.02 x 10²³molecules
= 1.88 x 10²³molecules of H₂O
