Two [hydrogen] atoms and one [oxygen] atom
Using the specific heat capacity formula:
q = mc ∆ t
60.0 J = (6g)(x)(11*C)
x = 0.9 J/g*C
Aluminum
Answer: the reaction will produce 15.3 g of
KCl.
explanation:
1. write the balanced equation.
2KClO
3
→
2KCl
+
3O
2
2. calculate the moles of
KClO
3
.
Moles of KClO
3
=
25.0
g KClO
3
×
1 mol KClO
3
122.55
g KClO
3
=
0.2046 mol KClO
3
3. calculate the moles of
KCl
.
Moles of KCl
=
0.2046
mol KClO
3
×
2 mol KCl
2
mol KClO
3
=
0.2046 mol KCl
4. calculate the mass of
KCl
.
Mass of KCl
=
0.2046
mol KCl
×
74.55 g KCl
1
mol KCl
=
15.3 g KCl
Answer:
Explanation:
The expression can be solved mathematically as follows:
1) 
Given
2) 
Definition of sum
3) 
/Associative property
4) 
Distributive property
5) 
Multiplication
6) 
Subtraction.
7) 
Multiplication/Associative property
8) 
Associative property
9) /Result
A, O2 has to be a reactant for combustion to burn
