The low temperature outside lowers the volume of the gas according to Charles' law because this law describes how a gas will behave at constant pressure. It shows that the volume of a given mass of a gas is directly proportional to the absolute temperature provided the pressure remains constant. An increase in temperature leads to an increase in volume while a decrease reduces the volume. This is due to the reduction in the distances traveled by the vibrating particles of the gas because of the lost kinetic energy.
Balanced equation: 2Na(s) + Cl₂(g) ---> 2NaCl(s)
when we have STP conditions, we can use this conversion: 1 mol = 22.4 L
first, we have to convert grams to molecules using the molar mass, and then use mole to mole ratio from the balanced equation.
molar mass of Na= 23.0 g/mol
ratio: 2 mol Na= 1 mol Cl₂ (based on coefficients of balanced equation)
calculations:
Answer:
-1 Coulomb meter = -2.997 × 10²⁹ Debye
Explanation:
Given:
Coulomb meter = -1 CM
Find:
In debye
Computation:
We know that,
1 Coulomb meter = 299,792,458,178,090,000,000,000,000,000 Debye
So,
-1 Coulomb meter = -299,792,458,178,090,000,000,000,000,000 Debye
-1 Coulomb meter = -2.997 × 10²⁹ Debye
Answer:
Initially
of nitrogen dioxide were in the container .
Explanation:
Volume of the container at low pressure and at room temperature =![V_1=3.4 L](https://tex.z-dn.net/?f=V_1%3D3.4%20L)
Number of moles in the container = ![n_1](https://tex.z-dn.net/?f=n_1)
After more addition of nitrogen gas at the same pressure and temperature.
Volume of the container after addition = ![V_2=5.11 L](https://tex.z-dn.net/?f=V_2%3D5.11%20L)
Number of moles in the container after addition=![n_2=2.28\times 10^{-2} mol](https://tex.z-dn.net/?f=n_2%3D2.28%5Ctimes%2010%5E%7B-2%7D%20mol)
Applying Avogadro's law:
(at constant pressure and temperature)
![\frac{V_1}{n_1}=\frac{V_2}{n_2}](https://tex.z-dn.net/?f=%5Cfrac%7BV_1%7D%7Bn_1%7D%3D%5Cfrac%7BV_2%7D%7Bn_2%7D)
![n_1=\frac{V_1\times n_2}{V_2}=\frac{3.4 L\times 2.28\times 10^{-2} mol}{5.11 L}](https://tex.z-dn.net/?f=n_1%3D%5Cfrac%7BV_1%5Ctimes%20n_2%7D%7BV_2%7D%3D%5Cfrac%7B3.4%20L%5Ctimes%202.28%5Ctimes%2010%5E%7B-2%7D%20mol%7D%7B5.11%20L%7D)
![n_1=1.51\times 10^{-2} mol](https://tex.z-dn.net/?f=n_1%3D1.51%5Ctimes%2010%5E%7B-2%7D%20mol)
Initially
of nitrogen dioxide were in the container .