All categories

2 years ago

If the reactants of a reaction have an initial mass of 25g what should the mass of the products be

Chemistry

1 answer:

Fynjy0 [20]2 years ago

7 0

Answer:

It remains the same

Explanation:

The law of conservation of mass states that, during a chemical reaction, the total mass of the products must be equal to the total mass of the reactants.

You might be interested in

Which of the following is true about incomplete dominance? Options: 1. Neither allele is completely dominant over the other alle

lions [1.4K]

Hello,

<span>3. The parents’ phenotypes are expressed equally in the offspring’s phenotype.</span>

4 0

2 years ago

Read 2 more answers

How many molecules of ethane ( C2H6) are present in 0.197g of C2H6?

gayaneshka [121]

C2H6/C2H6=1

dasdwasdwasdwasdasdwa

8 0

3 years ago

What is the property of a neutron?

UNO [17]

Answer:

A) 0 charge

Explanation:

neutron=neutral

7 0

3 years ago

PLS HELP I WILL MARK BRAINLIEST NO LINKS OR PDFS AND PLSEXPLAIN YOUR ANSWER CLEARLY THANKYOU

Butoxors [25]

Answer:If each side of the equation has the same number of atoms of a given element, that element is balanced. If all elements are balanced, the equation is balanced. - online resource

Explanation: if not im sorry

8 0

3 years ago

Read 2 more answers

A gas used to extinguish fires is composed of 75 % CO2 and 25 % N2. It is stored in a 5 m3 tank at 300 kPa and 25 °C. What is th

tatyana61 [14]

Answer : The partial pressure of the $CO_2$ in the tank in psia is, 32.6 psia.

Explanation :

As we are given 75 % $CO_2$ and 25 % $N_2$ in terms of volume.

First we have to calculate the moles of $CO_2$ and $N_2$ .

$\text{Moles of }CO_2=\frac{\text{Volume of }CO_2}{\text{Volume at STP}}=\frac{75}{22.4}=3.35mole$

$\text{Moles of }N_2=\frac{\text{Volume of }N_2}{\text{Volume at STP}}=\frac{25}{22.4}=1.12mole$

Now we have to calculate the mole fraction of $CO_2$ .

$\text{Mole fraction of }CO_2=\frac{\text{Moles of }CO_2}{\text{Moles of }CO_2+\text{Moles of }N_2}$

$\text{Mole fraction of }CO_2=\frac{3.35}{3.35+1.12}=0.75$

Now we have to calculate the partial pressure of the $CO_2$ gas.

$\text{Partial pressure of }CO_2=\text{Mole fraction of }CO_2\times \text{Total pressure of gas}$

$\text{Partial pressure of }CO_2=0.75mole\times 300Kpa=225Kpa=225Kpa\times \frac{0.145\text{ psia}}{1Kpa}=32.625\text{ psia}$

conversion used : (1 Kpa = 0.145 psia)

Therefore, the partial pressure of the $CO_2$ in the tank in psia is, 32.6 psia.

3 0

2 years ago