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katrin2010 [14]
3 years ago
11

A 4 kg rock is rolling 10 m/s find its kinetic energy

Chemistry
1 answer:
larisa [96]3 years ago
5 0
The answer is 200 J

The kinetic energy (KE) is:
KE = 1/2 m * v²
m - mass of the object
v - velocity of the object

We have:
m = 4 kg
v = 10 m/s

KE = 1/2 * 4 kg * 10² m/s
KE = 200 J
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Matter is anything that has volume and/or mass.

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Draw the structure with the molecular formula C6H14O that most likely produced the below IR and 1H NMR. The 13C NMR data is 78.3
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3 years ago
Which isotope will spontaneously decay and emit particles with a charge of +2?
VikaD [51]

Answer: The correct option is 4.

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_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_2^4\alpha

2) Beta-minus decay: It is a decay in which a beta particle is released. The  beta particle released has a mass number of 0 and a charge of (-1).

_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta

3) Beta-plus decay: It is a decay process in which a positron is released. The positron released has a mass number of 0 and has a charge of +1.

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For the given options:

Option 1: This nuclei will undergo beta-plus decay process to form _{25}^{53}\textrm{Mn}

_{26}^{53}\textrm{Fe}\rightarrow _{25}^{53}\textrm{Mn}+_{+1}^0\beta

Option 2: This nuclei will undergo beta-minus decay process to form _{80}^{198}\textrm{Hg}

_{79}^{198}\textrm{Au}\rightarrow _{80}^{198}\textrm{Hg}+_{-1}^0\beta

Option 3: This nuclei will undergo a beta minus decay process to form _{56}^{137}\textrm{Ba}

_{55}^{137}\textrm{Cs}\rightarrow _{56}^{137}\textrm{Ba}+_{-1}^0\beta

Option 4: This nuclei will undergo an alpha decay process to form _{85}^{216}\textrm{At}

_{87}^{220}\textrm{Fr}\rightarrow _{85}^{216}\textrm{At}+_2^4\alpha

Hence, the correct option is 4.

7 0
4 years ago
Read 2 more answers
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