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kotykmax [81]
3 years ago
7

(3a^4b)(5ab^2)-(a^5b^2)(9b)

Mathematics
1 answer:
Sliva [168]3 years ago
5 0

Answer:

The expanded value of the given expression is

(3a^4b)(5ab^2)-(a^5b^2)(9b)=6a^5b^3

Step-by-step explanation:

Given expression is                                                                              

(3a^4b)(5ab^2)-(a^5b^2)(9b)

To find the value of the given expression:

(3a^4b)(5ab^2)-(a^5b^2)(9b)=15a^5b^3-9a^5b^3

(By multiplying the products and doing algebraci subtracion of the above expression)

Now taking the common terms in the above equation we get

(3a^4b)(5ab^2)-(a^5b^2)(9b)=3a^5b^3(5-3)

                                             =3a^5b^3(2)

                                             =6a^5b^3

Therefore the expanded value of the given expression is

(3a^4b)(5ab^2)-(a^5b^2)(9b)=6a^5b^3

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3 years ago
How to integrate 1/(1-y)^2
Akimi4 [234]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/866966

_______________


Evaluate the indefinite integral:

\mathsf{\displaystyle\int\!\dfrac{1}{(1-y)^2}\,dy}\\\\\\ =\mathsf{\displaystyle\int\!\dfrac{-1}{(1-y)^2}\cdot (-1)\,dy}\\\\\\ =\mathsf{\displaystyle- \int\!(1-y)^{-2}\cdot (-1)\,dy\qquad\quad(i)}


Substitution:

\begin{array}{lcl} \mathsf{1-y=u}&\quad\Rightarrow\quad&\mathsf{y=1-u}\\\\ &&\mathsf{dy=-1\,du} \end{array}


So the integral \mathsf{(i)} becomes

=\mathsf{\displaystyle -\int\! u^{-2}\,du}\\\\\\ =\mathsf{-\,\dfrac{u^{-2+1}}{-2+1}+C}\\\\\\ =\mathsf{-\,\dfrac{u^{-1}}{-1}+C}\\\\\\ =\mathsf{u^{-1}+C}\\\\\\ =\mathsf{\dfrac{1}{u}+C}

=\mathsf{\dfrac{1}{1-y}+C}\\\\\\\ \therefore~~\boxed{\begin{array}{c}\mathsf{\displaystyle\int\!\dfrac{1}{(1-y)^2}\,dy=\dfrac{1}{1-y}+C} \end{array}}\qquad\quad\checkmark


I hope this helps. =)


Tags:  <em>indefinite integral fraction rational substitution power differential calculus</em>

3 0
3 years ago
.5674 to the nearest whole number
mestny [16]

Answer:3

Step-by-step explanation:5674

4 0
2 years ago
Guys this is a real problem!!! Will mark brainliest!!
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3 years ago
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3 years ago
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