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kotykmax [81]
3 years ago
7

(3a^4b)(5ab^2)-(a^5b^2)(9b)

Mathematics
1 answer:
Sliva [168]3 years ago
5 0

Answer:

The expanded value of the given expression is

(3a^4b)(5ab^2)-(a^5b^2)(9b)=6a^5b^3

Step-by-step explanation:

Given expression is                                                                              

(3a^4b)(5ab^2)-(a^5b^2)(9b)

To find the value of the given expression:

(3a^4b)(5ab^2)-(a^5b^2)(9b)=15a^5b^3-9a^5b^3

(By multiplying the products and doing algebraci subtracion of the above expression)

Now taking the common terms in the above equation we get

(3a^4b)(5ab^2)-(a^5b^2)(9b)=3a^5b^3(5-3)

                                             =3a^5b^3(2)

                                             =6a^5b^3

Therefore the expanded value of the given expression is

(3a^4b)(5ab^2)-(a^5b^2)(9b)=6a^5b^3

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For what value of x is the figure a rectangle?
Anna [14]

Step-by-step explanation:

step 1. 4x + 27 + 3x = 90 (definition of a rectangle)

step 2. 7x = 63 (collect like terms. subtract 27 from both sides)

step 3. x = 9 (divide both sides by 7)

6 0
3 years ago
Given these angles: m∠3 = 82°, m∠4 = 98°.
RSB [31]
These angles are supplementary.
Complementary angles add up to 90 degrees. Supplementary angles add up to 180 degrees. 82 degrees + 98 degrees = 180 degrees.
8 0
3 years ago
[HELP] For j(x) = <img src="https://tex.z-dn.net/?f=5%5Ex%5E-%5E3" id="TexFormula1" title="5^x^-^3" alt="5^x^-^3" align="absmidd
Alina [70]

The difference quotient of the function that has been presented to us will turn out to be 5.

<h3>How can I calculate the quotient of differences?</h3>

In this step, we wish to determine the difference quotient for the function that was supplied.

To begin, keep in mind that the difference quotient may be calculated by:

Lim h->0 \frac{f(x+h)-f(x)}{h}

Now, for the purpose of the function, we need this:

Then we will have:

$$\begin{aligned}&\lim _{h \rightarrow 0} \frac{j(x+h)-j(x)}{h} \\&\lim _{h \rightarrow 0} \frac{5 *(x+h)-3-5 * x+3}{h} \\&\lim _{h \rightarrow 0} \frac{5 x+5 h-3-5 x+3}{h} \\&\lim _{h \rightarrow 0} \frac{5 h}{h}=5\end{aligned}$$

j(x) = 5x - 3

Then the following will be true:

Therefore, 5 is the value of the difference quotient for j(x) is %

Read the following if you are interested in finding out more about difference quotients:

brainly.com/question/15166834

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6 0
1 year ago
1.Solve for w.
iren [92.7K]
Hi there,

1) 
6 + (w - 10) = 5
6 + w - 10 = 5
- 4 + w = 5
w = 5 + 4

Hence, W = 9

2)
2/3 + y - 1/9 = 7/9
5/9 + y = 7/9
y= 7/9 - 5/9

Hence, Y = 2/9

4)
4x - 3/2x - 15/4 = 3/8
32x - 12x - 30 = 3
20x - 30 = 3
20x = 3 + 30
20x = 33

Hence, the answer is 33/20

5)
0.7(3s + 4) - 1.1s = 7.9
2.1s + 2.8 - 1.1 = 7.9
s + 2.8 = 7.9
s = 7.9 - 2.8

Hence, the answer is 5.1

Hope this all helps :)
8 0
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Answer:

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