It's A; decomposition reactions involve one reactant becoming 2 or more products.
Answer:
volume = 1.04 dm^3
Explanation:
Data:
volume = ?
Molarity, M = 0.25M
mass = 28.5g
Molar mass = 110.25g
Moles = ?
Solution:
First find number of moles,
moles = mass in gram / molar mass
= 28.5 / 110.25
= 0.258
≈ 0.26 moles
Now,
Molarity = ![\frac{no. of moles}{volume in dm^3}](https://tex.z-dn.net/?f=%5Cfrac%7Bno.%20of%20moles%7D%7Bvolume%20in%20dm%5E3%7D)
So,
Volume in dm^3 = ![\frac{no. of moles}{molarity}](https://tex.z-dn.net/?f=%5Cfrac%7Bno.%20of%20moles%7D%7Bmolarity%7D)
= 0.26 / 0.25
Volume = 1.04 dm^3
Answer:
is most likely to gain one electron to form an ion with a 1- charge.
This is an incomplete question, here is a complete question.
A certain first-order reaction has a rate constant of 5.50 × 10⁻³ s⁻¹. How long will it take for the reactant concentration to drop to 1/8 of its initial value?
Answer : The time taken will be, 378.1 s
Explanation :
Expression for rate law for first order kinetics is given by:
![t=\frac{2.303}{k}\log\frac{a}{a-x}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B2.303%7D%7Bk%7D%5Clog%5Cfrac%7Ba%7D%7Ba-x%7D)
where,
k = rate constant = ![5.50\times 10^{-3}s^{-1}](https://tex.z-dn.net/?f=5.50%5Ctimes%2010%5E%7B-3%7Ds%5E%7B-1%7D)
t = time passed by the sample = ?
a = let initial amount of the reactant = x
a - x = amount left after decay process = ![\frac{x}{8}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B8%7D)
Now put all the given values in above equation, we get
![t=\frac{2.303}{5.50\times 10^{-3}}\log\frac{x}{(\frac{x}{8})}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B2.303%7D%7B5.50%5Ctimes%2010%5E%7B-3%7D%7D%5Clog%5Cfrac%7Bx%7D%7B%28%5Cfrac%7Bx%7D%7B8%7D%29%7D)
![t=378.1s](https://tex.z-dn.net/?f=t%3D378.1s)
Thus, the time taken will be, 378.1 s
Answer: use methods to clean up ocean oil spills
Explanation: