3 years ago

If g(x) = 3x^2+2x-1. Find g(-1).

Mathematics

1 answer:

Mandarinka [93]3 years ago

5 0

Step-by-step explanation:

g(x) = 3x² + 2x - 1

g(-1) = 3(-1)² + 2(-1) - 1

= 3(1) -2 -1

= 3 - 3

= 0

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Answer:

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Answer:

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Step-by-step explanation:

We want to verify that:

$\cot(x) \: { \sec}^{4} x = \cot(x) + 2 \tan(x) + { \tan}^{3} x$

Verifying from left, we have

$\cot(x) \: { \sec}^{4} x = \cot(x) \: ( 1 + { \tan}^{2} x )^{2}$

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We expand to get:

$\cot(x) \: { \sec}^{4} x = \cot(x) \: + \cot(x){ 2\tan}^{2} x +\cot(x) { \tan}^{4} x$

We simplify to get:

$\cot(x) \: { \sec}^{4} x = \cot(x) \: + 2 \frac{ \cos(x) }{\sin(x) ) } \times \frac{{ \sin}^{2} x}{{ \cos}^{2} x} +\frac{ \cos(x) }{\sin(x) ) } \times \frac{{ \sin}^{4} x}{{ \cos}^{4} x}$

Cancel common factors:

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2 years ago

If g(x) = 3x^2+2x-1. Find g(-1).​

If g(x) = 3x^2+2x-1. Find g(-1).