Multiply 60 by 15,subtract 60 by the product. after you have subtracted divide it by 4.
7+(10−4)2:4⋅231=7+62:4⋅81=7+36:4⋅81=7+9⋅81=7+89=7+181=881
Answer:
17, -3, -13, -18, -23
Step-by-step explanation:
Plug in the x side into the equation so
g(-4) = -5(-4) -3
g(-4) = 20-3
g(-4) = 17
Therefore that answer is 17
Then you do that for all of them, I don't have the time to do them all but that's the concept for all of them. Hope this helps and hopefully it's not too late. Sorry!
Answer:
A) See the picture
B) 14
C) 45%
Step-by-step explanation:
A) To create a histogram like the one on the picture you can use an online tool like socscistatistics where the number of classes is customizable
B) Because the question B and C have to be responded using a frequency table with 8 classes the answer is 14; the method of using cumulative frequency tables should only be considered as a way of estimation, that is because you obtain values that depend on your choice of class intervals. The way to get a better answer would be to use all the scores in the distribution
Pc1 = 100*(4/40) = 10
Pc2 = 100*(4/40) = 10
Pc3 = 100*(3/40) = 7.5
Pc4 = 100*(11/40) = 27.5
Pc5 = 100*(5/40) = 12.5
Pc6 = 100*(4/40) = 10
Pc7 = 100*(7/40) = 17.5
Pc8 = 100*(2/40) = 5
Pc8 + Pc7 + Pc6 + Pc5 + Pc4 + Pc3 + Pc2 = 90%
Therefore, From class 8 to class 2 is the top 90% of the applicants and the minimum score is 14.
C) Scores equal to or greater than 20 are from class 8 to class 5
Pc8 + Pc7 + Pc6 + Pc5 = 45%
Answer:4,891 are undergraduate students .
Step-by-step explanation:
Total Number of students = 6700
Percentage of Undergraduate students = 73%
Number of Undergraduatre students = Percentage of Undergraduate students x Total Number of students
= 73% x 6700
73/100 x6700
=4,891 are undergraduate students .