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deff fn [24]
3 years ago
13

A boiler is used to heat steam at a brewery to be used in various applications such as heating water to brew the beer and saniti

zing the brewing tanks. 73.0% of the heat produced by the boiler is used to create saturated steam at 12.0 bars (absolute) from liquid water at 22' C. If 140 m3/h of steam is needed, what rate of heat does the boiler output?
Chemistry
1 answer:
IgorLugansk [536]3 years ago
3 0
  <span>Q= m (h(p=10.0 bar,T= boiling temperature at p) - h( p,θ= 22°C)). The enthalpies are in J/Kg and are read from a steam table. Unfortunately I don't know the initial pressure at 22°C so I leave this work to you. 
m= ρ(12 bar, T) V with V= 0.73* 140 m³ /hr = 0.027 m³/s -> Q</span>
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<u>Answer:</u> The theoretical yield of acetanilide is 6.5 grams.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For aniline:</u>

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  • <u>For acetic anhydride:</u>

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\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

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Density of acetic anhydride = 1.08 g/mL

Putting values in above equation:

1.08g/mL=\frac{\text{Mass of acetic anhydride}}{5.625mL}\\\\\text{Mass of acetic anhydride}=(1.08g/mL\times 5.625mL)=6.08g

Given mass of acetic anhydride = 6.08 g

Molar mass of acetic anhydride = 102.1 g/mol

Putting values in equation 1, we get:

\text{Moles of acetic anhydride}=\frac{6.08g}{102.1g/mol}=0.06mol

The chemical equation for the reaction of aniline and acetic anhydride follows:

C_6H_5NH_2+CH_3COOCOCH_3\rightarrow C_6H_5NHCOCH_3+CH_3COOH

By Stoichiometry of the reaction:

1 mole of aniline reacts with 1 mole of acetic anhydride

So, 0.048 moles of aniline will react with = \frac{1}{1}\times 0.048=0.048mol of acetic anhydride

As, given amount of acetic anhydride is more than the required amount. So, it is considered as an excess reagent.

Thus, aniline is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of aniline produces 1 mole of acetanilide

So, 0.048 moles of aniline will produce = \frac{1}{1}\times 0.048=0.048mol of acetanilide

Now, calculating the theoretical yield of acetanilide by using equation 1:

Moles of acetanilide = 0.048 moles

Molar mass of acetanilide = 135.17 g/mol

Putting values in equation 1, we get:

0.048mol=\frac{\text{Mass of acetanilide}}{135.17g/mol}\\\\\text{Mass of acetanilide}=(0.048mol\times 135.17g/mol)=6.5g

Hence, the theoretical yield of acetanilide is 6.5 grams.

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