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3 years ago

If one wheel on bob's model 4 inches across, how many inches across is the actual wheel on his bike? Explain.

Mathematics

1 answer:

emmasim [6.3K]3 years ago

4 0

Answer:

There is not enough information to answer this question. Is there perhaps a diagram or table provided?

Step-by-step explanation:

You might be interested in

3 to the fourth power +9

Igoryamba

Answer:

Step-by-step explanation:

3*3=9

9*3=27

27*3=81

3 0

2 years ago

Read 2 more answers

Lagrange multipliers have a definite meaning in load balancing for electric network problems. Consider the generators that can o

Ivahew [28]

Answer:

The load balance $(x_1,x_2,x_3)=(545.5,272.7,181.8)$ Mw minimizes the total cost

Step-by-step explanation:

<u>Optimizing With Lagrange Multipliers</u>

When a multivariable function f is to be maximized or minimized, the Lagrange multipliers method is a pretty common and easy tool to apply when the restrictions are in the form of equalities.

Consider three generators that can output xi megawatts, with i ranging from 1 to 3. The set of unknown variables is x1, x2, x3.

The cost of each generator is given by the formula

$\displaystyle C_i=3x_i+\frac{i}{40}x_i^2$

It means the cost for each generator is expanded as

$\displaystyle C_1=3x_1+\frac{1}{40}x_1^2$

$\displaystyle C_2=3x_2+\frac{2}{40}x_2^2$

$\displaystyle C_3=3x_3+\frac{3}{40}x_3^2$

The total cost of production is

$\displaystyle C(x_1,x_2,x_3)=3x_1+\frac{1}{40}x_1^2+3x_2+\frac{2}{40}x_2^2+3x_3+\frac{3}{40}x_3^2$

Simplifying and rearranging, we have the objective function to minimize:

$\displaystyle C(x_1,x_2,x_3)=3(x_1+x_2+x_3)+\frac{1}{40}(x_1^2+2x_2^2+3x_3^2)$

The restriction can be modeled as a function g(x)=0:

$g: x_1+x_2+x_3=1000$

$g(x_1,x_2,x_3)= x_1+x_2+x_3-1000$

We now construct the auxiliary function

$f(x_1,x_2,x_3)=C(x_1,x_2,x_3)-\lambda g(x_1,x_2,x_3)$

$\displaystyle f(x_1,x_2,x_3)=3(x_1+x_2+x_3)+\frac{1}{40}(x_1^2+2x_2^2+3x_3^2)-\lambda (x_1+x_2+x_3-1000)$

We find all the partial derivatives of f and equate them to 0

$\displaystyle f_{x1}=3+\frac{2}{40}x_1-\lambda=0$

$\displaystyle f_{x2}=3+\frac{4}{40}x_2-\lambda=0$

$\displaystyle f_{x3}=3+\frac{6}{40}x_3-\lambda=0$

$f_\lambda=x_1+x_2+x_3-1000=0$

Solving for \lambda in the three first equations, we have

$\displaystyle \lambda=3+\frac{2}{40}x_1$

$\displaystyle \lambda=3+\frac{4}{40}x_2$

$\displaystyle \lambda=3+\frac{6}{40}x_3$

Equating them, we find:

$x_1=3x_3$

$\displaystyle x_2=\frac{3}{2}x_3$

Replacing into the restriction (or the fourth derivative)

$x_1+x_2+x_3-1000=0$

$\displaystyle 3x_3+\frac{3}{2}x_3+x_3-1000=0$

$\displaystyle \frac{11}{2}x_3=1000$

$x_3=181.8\ MW$

And also

$x_1=545.5\ MW$

$x_2=272.7\ MW$

The load balance $(x_1,x_2,x_3)=(545.5,272.7,181.8)$ Mw minimizes the total cost

5 0

3 years ago

Find the difference between the lengths of the longest and shortest sides of a rectangle if its area is 924 square milimetres an

BigorU [14]

Length =l

Height = h

Area function = l * h = 924

Perimeter function = 2i + 2h = 122

Divide by 2

I + h = 61.

Plug in I or h for the other variable

I * (61 - I) = 924

61i - i^2 = 924

Factor the function

(-I + 28)(I - 33) = 0

l = 33 as l cannot be negative

61 - 33 = 28

h = 28

Difference between h and l is 33-28=5

6 0

1 year ago

Find the missing length and round to the nearest tenth if necessary

cricket20 [7]

C= 6.7

A^2 + B^2 = C^2
6^2 + 3^2 = C^2
36+9 = 45
Square root 45 = 6.7

6 0

2 years ago

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Someone please help me I suck @ simplifying thank you

dsp73

To solve this question, you would need to find the common denominator among the 2 fractions. In this case it would be

72.

Then multiply numbers to both of the fractions to get to the bottom number in both fractions equaling 72.

40/72 + 27/72 =67/72.

Try to reduce to lowest terms by dividing a common number from both of them if possible.

5 0

3 years ago

Read 2 more answers