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3 years ago

What can you conclude and reason

Mathematics

1 answer:

SSSSS [86.1K]3 years ago

6 0

Answer:

ABC is an isosceles triangle.

Because it consists of two congruent triangles created by CD, side AC = CB, making it an isosceles triangle.

Step-by-step explanation:

I can conclude that triangle ABC is an isosceles triangle.

Perpendicular means intersecting at 90°. Bisector means intersecting at the midpoint, halfway between the two ends.

Since CD is dropped from vertex C and is a perpendicular bisector of AB, angle C is also bisected.

Therefore angle C for both triangles CDA and CDB is of equal measure.

We know angle D for both triangle CDA and CDB is of equal measure, 90°, because CD is a <em>perpendicular </em>bisector of AB.

The two triangles also share the same side CD.

Triangles CDA and CDB are congruent for having 2 equal angles and 1 equal side (ASA property).

Since they are congruent, AD = AB and AC = CB. Therefore triangle ABC is an isosceles triangle.

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In the figure below, lines 1 and 2 are parallel. Lines 3 and 4 are also parallel.

attashe74 [19]

I don’t see a diagram, but I assume that you must use these things.

Opposite interior angles. (Which are equal)
Same side interior angles (which are supplementary or they add up to 180)
Corresponding angles (which are equal)
Vertical angles (which are equal)

5 0

3 years ago

Please help. due today.

guapka [62]

Answer:

1, 1/2, 1 1/2

Step-by-step explanation:

Question 1

20 divided by 18 is 1.1

So the answer is closest to 1

Question 2

9 divided by 20 is 0.45

So the answer is closest to 1/2

Question 3

7 divided by 5 is 1.4

So the answer is closest to 1 1/2

Hope this helps!

3 0

3 years ago

A box contains 24 transistors,4 of which are defective. If 4 are sold at random,find the following probabilities. i. Exactly 2 a

zavuch27 [327]

SOLUTION

This is a binomial probability. For i, we will apply the Binomial probability formula

i. Exactly 2 are defective

Using the formula, we have

$\begin{gathered} P_x=^nC_x\left(p^x\right?\left(q^{n-x}\right) \\ Where\text{ } \\ P_x=binomial\text{ probability} \\ x=number\text{ of times for a specific outcome with n trials =2} \\ p=\text{ probability of success = }\frac{4}{24}=\frac{1}{6} \\ q=probability\text{ of failure =1-}\frac{1}{6}=\frac{5}{6} \\ ^nC_x=\text{ number of combinations = }^4C_2 \\ n=\text{ number of trials = 4} \end{gathered}$

Note that I made the probability of being defective as the probability of success = p

and probability of none defective as probability of failure = q

Exactly 2 are defective becomes the binomial probability

$\begin{gathered} P_x=^4C_2\times\lparen\frac{1}{6})^2\times\lparen\frac{5}{6})^{4-2} \\ P_x=6\times\frac{1}{36}\times\frac{25}{36} \\ P_x=\frac{25}{216} \\ =0.1157 \end{gathered}$

Hence the answer is 0.1157

(ii) None is defective becomes