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Kisachek [45]
3 years ago
14

A kayaker paddles at 4.0 m/s in a direction 30° south of west. He then turns and paddles at 3.7 m/s in a direction 20° west of s

outh.
What is the magnitude of the kayaker’s resultant velocity? Round your answer to the nearest tenth.

___m/s
What is the direction of the kayaker’s resultant velocity?

___ ° south of west
please help
Physics
2 answers:
user100 [1]3 years ago
7 0
7.2 m/s 

49 degrees south of west

Gre4nikov [31]3 years ago
5 0

Answer: The magnitude of the kayaker's resultant velocity = 7.23 m/s

and the direction is 49.26° south of west.

Explanation:

Initial velocity, u = 4.0 m/s 30° south of west.

Final velocity, v = 3.7 m/s 20° west of south °≈ 70° south of west.

Writing in terms of component:

u = -4.0 cos 30 i - 4.0 sin 30 j = -3.46 i -2.0 j

v = -3.7 cos 70 i - 3.7 sin 70 j = -1.26 i - 3.48 j

Resultant velocity = addition of the two velocity vectors

R = (-3.46 i -2.0 j)+(-1.26 i - 3.48 j) = -4.72 i - 5.48 j

Magnitude of the vector = √(-4.72)²+( - 5.48)² = 7.23 m/s

Direction of the resultant velocity vector, θ = tan⁻¹ (-5.48÷ (-4.72)) = 49.26° south of west.

Thus, the magnitude of the kayaker's resultant velocity = 7.23 m/s

and the direction is 49.26° south of west.

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vaieri [72.5K]

Answer:

(A). The resulting nucleus is Fr.

(B). The resulting nucleus is Po.

(C). The resulting nucleus is Ne

(D). The resulting nucleus is Tc.

Explanation:

Given that,

A nucleus undergoes a nuclear decay.

(A). In alpha decay,

We know that,

When the nucleus emit alpha particle then atomic mass of particle reduce by 4 and atomic number reduce by 2.

We need to calculate the resulting nucleus

Using given data

^{227}_{89}Ac\Rightarrow ^{227-4}_{89-2}X

^{227}_{89}Ac\Rightarrow ^{223}_{87}Fr

The resulting nucleus is Fr.

(B). In beta-minus decay,

We know that,

When the nucleus emit beta- minus particle then atomic mass of particle is same and atomic number increase by 1.

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Using given data

^{211}_{83}Bi\Rightarrow ^{211}_{83+1}X

^{211}_{83}Bi\Rightarrow ^{211}_{84}Po

The resulting nucleus is Po.

(C). In beta-plus decay,

We know that,

When the nucleus emit beta- plus particle then atomic mass of particle is same and atomic number decrease by 1.

We need to calculate the resulting nucleus

Using given data

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^{22}_{11}Na\Rightarrow ^{22}_{10}Ne

The resulting nucleus is Ne.

(D). In gamma decay,

We know that,

When the nucleus emit gamma particle then atomic mass and atomic number of particle is same.

We need to calculate the resulting nucleus

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(B). The resulting nucleus is Po.

(C). The resulting nucleus is Ne

(D). The resulting nucleus is Tc.

4 0
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Suppose a 2.0kg bird is flying at a speed of of 1m/s. It’s kinetic energy would be what?
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As we know that the formula of kinetic energy will be

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now here we know that

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3 years ago
Radiation from the Sun The intensity of the radiation from the Sun measured on Earth is 1360 W/m2 and frequency is f = 60 MHz. T
Zina [86]

a) Total power output: 3.845\cdot 10^{26} W

b) The relative percentage change of power output is 1.67%

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Explanation:

a)

The intensity of electromagnetic radiation is given by

I=\frac{P}{A}

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The area to be considered is area of a sphere of radius

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b)

The energy of the solar radiation is directly proportional to its frequency, given the relationship

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Also, the power output of the Sun is directly proportional to the energy,

P=\frac{E}{t}

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c)

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I=\frac{3.910\cdot 10^{26}}{7.24\cdot 10^{23}}=540 W/m^2

Learn more about electromagnetic radiation:

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