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Kisachek [45]
3 years ago
14

A kayaker paddles at 4.0 m/s in a direction 30° south of west. He then turns and paddles at 3.7 m/s in a direction 20° west of s

outh.
What is the magnitude of the kayaker’s resultant velocity? Round your answer to the nearest tenth.

___m/s
What is the direction of the kayaker’s resultant velocity?

___ ° south of west
please help
Physics
2 answers:
user100 [1]3 years ago
7 0
7.2 m/s 

49 degrees south of west

Gre4nikov [31]3 years ago
5 0

Answer: The magnitude of the kayaker's resultant velocity = 7.23 m/s

and the direction is 49.26° south of west.

Explanation:

Initial velocity, u = 4.0 m/s 30° south of west.

Final velocity, v = 3.7 m/s 20° west of south °≈ 70° south of west.

Writing in terms of component:

u = -4.0 cos 30 i - 4.0 sin 30 j = -3.46 i -2.0 j

v = -3.7 cos 70 i - 3.7 sin 70 j = -1.26 i - 3.48 j

Resultant velocity = addition of the two velocity vectors

R = (-3.46 i -2.0 j)+(-1.26 i - 3.48 j) = -4.72 i - 5.48 j

Magnitude of the vector = √(-4.72)²+( - 5.48)² = 7.23 m/s

Direction of the resultant velocity vector, θ = tan⁻¹ (-5.48÷ (-4.72)) = 49.26° south of west.

Thus, the magnitude of the kayaker's resultant velocity = 7.23 m/s

and the direction is 49.26° south of west.

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Unpolarized light of intensity I0 = 950 W/m2 is incident upon two polarizers. The first has its polarizing axis vertical, and th
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Intensity of the light (first polarizer) (I₁) = 425 W/m²

Intensity of the light (second polarizer) (I₂) = 75.905 W/m²

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b. Intensity of the light (second polarizer)

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a. Intensity of the light (first polarizer)

Intensity of the light (first polarizer) (I₁) = I₀ / 2

Intensity of the light (first polarizer) (I₁) = 950 / 2

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b. Intensity of the light (second polarizer)

Intensity of the light (second polarizer) (I₂) = (I₁)cos²θ

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Calculate the pressure exerted by a 4000N camel on the sand. The camel’s feet have a
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Answer:

The pressure exerted by camel feet is <u>2000 N/m²</u>.

Step-by-step explanation:

<h3><u>Solution</u> :</h3>

Here, we have given that ;

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  • Total area of camel feet = 2 m²

We need to find the pressure exerted by camel feet.

As we know that :

{\longrightarrow{\pmb{\sf{Pressure= \dfrac{Area}{Force}}}}}

Substituting all the given values in the formula to find the pressure exerted by camel feet.

\begin{gathered} \begin{array}{l} {\longrightarrow{\sf{Pressure= \dfrac{Area}{Force}}}} \\  \\ {\longrightarrow{\sf{Pressure= \dfrac{4000}{2}}}}  \\  \\ {\longrightarrow{\sf{Pressure= \cancel{\dfrac{4000}{2}}}}} \\  \\ {\longrightarrow{\sf{Pressure= 2000 \: N/{m}^{2}}}} \\  \\\star \:  \small\underline{\boxed{\sf{\purple{Pressure= 2000 \: N/{m}^{2}}}}} \end{array}\end{gathered}

Hence, the pressure exerted by camel feet is 2000 N/m².

\rule{300}{2.5}

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