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4 years ago

12

Explain what happens to the motion of a particle as a wave passes through a medium. How is the motion of the particles like the

motion of a mass on a spring

1 answer:

bezimeni [28]4 years ago

3 0

As they vibrate, they pass the disturbance of energy to the particles next to them, which passes the energy to the particles next to them, and so on.
Energy travels down the spring and reflected like the motion of a mass on a spring.

<u>Explanation</u>:

Particle motion is the superposition of a large component due to the fluid drag toward the filter barrier and a random component due to Brownian motion.

The particles of the medium just vibrate in place. As they vibrate, they pass the unsettling influence of energy to the particles beside them, which passes the energy to the particles by them, etc.

Energy goes down the spring and reflected like the movement of a mass on a spring.

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Which force is reasonable for making fusion possible in the sun?

andreev551 [17]

The force is reasonable for making fusion possible in the Sun is heat energy.

<h3>What is nuclear fission and fusion?</h3>

When the slow moving neutrons are bombarded with the heavy radioactive nuclei, the product is the more number of neutrons are produced with the large amount of energy. This multiplying process is called nuclear fusion.

The amount of energy produced in such a reaction can be calculated using the equivalence of mass and energy relationship.

E = mc²

The same happens in nuclear fusion where large amount of energy is needed to make more heavy nuclei.

Thus, fusion requires heat energy to continue the reaction.

Learn more about nuclear fusion and fission.

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8 0

2 years ago

The potential energy of a particle as a function of position will be given as U(x) = A x2 + B x + C, where U will be in joules w

satela [25.4K]

Answer:

F = - 2 A x - B

Explanation:

The force and potential energy are related by the expression

F = - dU / dx i ^ -dU / dy j ^ - dU / dz k ^

Where i ^, j ^, k ^ are the unit vectors on the x and z axis

The potential they give us is

U (x) = A x² + B x + C

Let's calculate the derivatives

dU / dx = A 2x + B + 0

The other derivatives are zero because the potential does not depend on these variables.

Let's calculate the strength

F = - 2 A x - B

3 0

3 years ago

The graph represents the reaction 2H2 + 02 32H20 as it reaches

Alex

Answer:

C and D

Explanation:

5 0

3 years ago

Read 2 more answers

Vector A has y-component Ay= +15.0 m . A makes an angle of 32.0 counterclockwise from the +y-axis. What is the x component of A?

Gemiola [76]

Answer:

x-component=-9.3 m

Magnitude of A=17.7m

Explanation:

We are given that

$A_y=+15 m$

$\theta=32^{\circ}$

We have to find the x-component of A and magnitude of A.

According to question

$A_y=\mid A\mid cos\theta$

Substitute the values then we get

$15=\mid A\mid cos32$

$\mid A\mid =\frac{15}{cos32}=\frac{15}{0.848}$

$\mid A\mid=17.7$ m

$tan\theta=\frac{perpendicular\;side}{Base}$

$tan32=\frac{A_x}{A_y}=\frac{A_x}{15}$

$0.62\times 15=A_x$

$A_x=9.3$

The value of x-component of A is negative because the vector A lie in second quadrant.

Hence, the x- component of A=-9.3 m

6 0

3 years ago

Read 2 more answers

If a circuit has a power of 50 W with a current of 4.5 A, what is the resistance in the circuit?

lawyer [7]

Answer:

${ \rm{power, \: p = current \times p.d}} \\ { \rm{50 = 4.5 \times (current \times resistance)}} \\ { \rm{50 = 4.5 \times (4.5 \times r)}} \\ { \rm{resistance = \frac{50}{ {4.5}^{2} } }} \\ \\ { \rm{resistance = 2.5 \: ohms}}$

8 0

2 years ago