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zavuch27 [327]
3 years ago
12

Law of Conservation of Energy.

Physics
1 answer:
Tems11 [23]3 years ago
3 0
Energy cannot be created nor be destroyed
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A museum curator moves artifacts into place on various different display surfaces. If the curator moves a 145 kg aluminum sculpt
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We are given the mass of an <span>aluminum sculpture which is 145 kg and a horizontal force equal to 668 Newtons. The coefficient of friction can be determined by dividing the horizontal force by the weight of the object. In this case, 668 N / 145 * 9.8 equal to coeff of friction of 0.47</span>
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How was mount Everest made? Please i am handing out 100 points
Simora [160]

Answer:

Mount Everest formed from a tectonic smashup between the Indian and Eurasian tectonic plates tens of millions of years ago.

Explanation:

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2 years ago
What is the frequency in hertz of a signal that repeats 80,000 times within one minute? What is its period?
Harman [31]

1333.3 is the frequency in the hertz of a signal that repeats 80,000 times within one minute. 0.00075 is its period.

The frequency of a repeated event is its number of instances per unit of time. In some cases, it is also referred to as temporal frequency or ordinary frequency to underline differences with spatial and angular frequencies, respectively.

The length of time it takes for a particle in a medium to complete one full vibrational cycle is the period of a wave. Being a time, a period is measured in time units like seconds, hours, days, or years. The Earth's orbit around the Sun has a duration of around 365 days, and one cycle of the Earth lasts 365 days.

frequency = cycle /second

frequency = 80000 / 60

frequency = 1333.3 hertz

Period = 1 / frequency

Period = 1 / 1,333.3

Period = 0.00075

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Facts about ecstasy
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3 years ago
You make a capacitor by cutting the 16.0-cm-diameter bottoms out of two aluminum pie plates, separating them by 3.25 mm, and con
dalvyx [7]

Answer:

The capacitance of your capacitor is 5.476 x 10⁻⁵ μF

Explanation:

Given;

diameter of the aluminum pie plates = 16 cm = 0.16 m

separation distance, d = 3.25 mm = 0.00325 m

voltage across the parallel plates = 6 V

C = \frac{\epsilon A}{d}

where;

C is the capacitance of your capacitor

ε is the permittivity of free space = 8.85 x 10⁻¹²  (F/m)

d is separation distance

A is the area of the plate = ¹/₄ (πd²) = 0.25 (π x 0.16²) = 0.02011 m²

C = \frac{8.85*10^{-12} *0.02011}{0.00325} = 5.476 * 10^{-11} \ F = \ 5.476 * 10^{-5} \mu F

Therefore, the capacitance of your capacitor is 5.476 x 10⁻⁵ μF

3 0
3 years ago
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