Answer:
Increasing speed.
Explanation:
In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.
This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.
Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.
Mathematically, acceleration is given by the equation;
![Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}](https://tex.z-dn.net/?f=Acceleration%20%28a%29%20%3D%20%5Cfrac%7Bfinal%20%5C%3B%20velocity%20%20-%20%20initial%20%5C%3B%20velocity%7D%7Btime%7D)
In this scenario, an object moves with a positive acceleration. Thus, the object is moving with an increasing speed and as such it has acceleration in the same direction as its velocity with respect to time.
The chemical equation needs to be balanced so that it follows the law of conservation of mass. A balanced chemical equation occurs when the number of the different atoms of elements in the reactants side is equal to that of the products side. Balancing chemical equations is a process of trial and error.
Answer:
![\Huge \boxed{\mathrm{2298.57 \ seconds}}](https://tex.z-dn.net/?f=%5CHuge%20%5Cboxed%7B%5Cmathrm%7B2298.57%20%5C%20seconds%7D%7D)
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Explanation:
![\displaystyle \sf Speed = \frac{Distance \ covered }{Time \ taken}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csf%20Speed%20%3D%20%5Cfrac%7BDistance%20%5C%20covered%20%20%7D%7BTime%20%5C%20taken%7D)
![\displaystyle \sf s = \frac{d }{t}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csf%20s%20%3D%20%5Cfrac%7Bd%20%20%7D%7Bt%7D)
The speed is 0.7 m/s.
The distance covered is 1609 m.
![\displaystyle \sf 0.7 = \frac{1609 }{t}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csf%200.7%20%3D%20%5Cfrac%7B1609%20%20%7D%7Bt%7D)
Multiplying both sides by <em>t</em>.
Then dividing both sides by 0.7.
![\displaystyle \sf t = \frac{1609 }{0.7}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csf%20t%20%3D%20%5Cfrac%7B1609%20%20%7D%7B0.7%7D)
![\sf t= 2298.57](https://tex.z-dn.net/?f=%5Csf%20t%3D%202298.57)
It would take 2298.57 seconds.
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Complete Question:
A beam of light from a monochromatic laser shines into a piece of glass. The glass has thickness Land index of refraction n=1.5. The wavelength of the laser light in vacuum is L/10 and its frequency is f. In this problem, neither the constant c nor its numerical value should appear in any of your answers.
How long does it take for a short pulse of light to travel from one end of the glass to the other?
Express your answer in terms of the frequency, f. Use the numeric value given for n in the introduction.
Answer:
15/f
Explanation:
Wavelength of the laser light, λ = L/10
Where L = Distance covered by the light
Refractive index, n = 1.5
Speed, v = λf
Since we are considering the laser light, the speed of light, c, will be used.
c = v
c = λf
c = (L/10)f
![speed = \frac{distance}{time}](https://tex.z-dn.net/?f=speed%20%3D%20%5Cfrac%7Bdistance%7D%7Btime%7D)
(L/10)f = L/t
f/10 = 1/t
t = 10/f
since the refractive index, n = 1.5
t = 1.5(10/f)
t = 15/f