Answer:
The density (more precisely, the volumetric mass density; also known as specific mass), of a substance is its mass per unit volume. The symbol most often used for density is ρ (the lower case Greek letter rho), although the Latin letter D can also be used.
Answer:
D
Explanation:
magnesium always lose 2 electrons
Answer:
The correct option is;
A) The water molecules group together in clumps.
Explanation:
To answer the question, we look at each option as follows
A) The water molecules group together in clumps
This does not aid dissolution of compounds as clumping excludes non polar molecules, making them less soluble.
B) The partial negative oxygen atom end of the water molecule surround cations.
When an ionic compound such as NaCl is dissolved in water, the oxygen atoms surround the positive Na⁺ cations in the solution.
C) The partial positive hydrogen atom end of the water molecule surround anions
When the ionic NaCl compound is dissolved in water, the hydrogen atoms surround the negative Cl⁻ anions in the solution.
D) The water molecules also dissolve nonelectrolytes by creating a hydration sphere around the molecule.
Water is able to dissolve nonelectrolytes by creating an hydration sphere or hydration shell around the molecule.
The answer is (D) microscopic. You can remember this, because the name is very close to "microscope," an instrument used to greatly magnify and observe tiny organisms and objects.
Answer:
a. NH3 is limiting reactant.
b. 44g of NO
c. 40g of H2O
Explanation:
Based on the reaction:
4NH₃(g) + 5O₂(g) → 4NO(g) + 6H₂O(l)
4 moles of ammonia reacts with 5 moles of oxygen to produces 4 moles of NO and 6 moles of water.
To find limiting reactant we need to find the moles of each reactant and using the balanced equation find which reactant will be ended first. Then, with limiting reactant we can find the moles of each reactant and its mass:
<em>a. </em><em>Moles NH3 -Molar mass. 17.031g/mol-</em>
25g NH3*(1mol/17.031g) = 1.47moles NH3
Moles O2 = 4 moles
For a complete reaction of 4 moles of O2 are required:
4mol O2 * (4mol NH3 / 5mol O2) = 3.2 moles of NH3.
As there are just 1.47 moles, NH3 is limiting reactant
b. Moles NO:
1.47moles NH3 * (4mol NO/4mol NH3) = 1.47mol NO
Mass NO -Molar mass: 30.01g/mol-
1.47mol NO * (30.01g/mol) = 44g of NO
c. Moles H2O:
1.47moles NH3 * (6mol H2O/4mol NH3) = 2.205mol H2O
Mass H2O -Molar mass: 18.01g/mol-
2.205mol H2O * (18.01g/mol) = 40g of H2O