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Bumek [7]
3 years ago
10

Which of the following is the balanced equation for P + O2 → P2O5? Question 3 options: A) 4P + O2 → 2P2O B) P + 5O2 → 2P2O5 C) 4

P + 5O2 → P2O5 D) 4P + 5O2 → 2P2O5
Chemistry
2 answers:
Masja [62]3 years ago
7 0

Your answer is <em>P + 5O2 → 2P2O5</em>.

This is the answer for K12 Chemistry. I just took the quiz.

Luden [163]3 years ago
4 0

Given equation:

P + O2 → P2O5

In order for the equation to be balanced, the stoichiometry of the atoms of one kind on the reactant side must be equal to that on the product

Reactants                                            Products

P = 1                                                       P = 2

O = 2                                                     O = 5

The balanced equation would be:

4P + 5O2 → 2P2O5

Reactants                                            Products

P = 4                                                      P = 4

O = 10                                                    O = 10

Ans: D)


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Scorpion4ik [409]

Answer:

26.3 mL

Explanation:

Step 1:

Obtaining an appropriate gas law from the ideal gas equation.

This is illustrated below:

From the ideal gas equation:

PV = nRT

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PV/T = nR

At this stage, we'll assume the number of mole (n) to be constant.

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We can thus, write the above equation as:

P1V1/T1 = P2V2/T2

The above equation is called the general gas equation.

Step 2:

Data obtained from the question. This includes the following:

Initial volume (V1) = 27.5 mL

Initial temperature (T1) = 22.0°C = 22.0°C + 273 = 295K

Initial pressure (P1) = 0.974 atm.

Final temperature (T2) = 15.0°C = 15.0°C + 273 = 288K

Final pressure (P2) = 0.993 atm

Final volume (V2) =..?

Step 3:

Determination of the final volume of the gas using the general gas equation obtained. This is illustrated below:

P1V1 /T1 = P2V2/T2

0.974 x 27.5/295 = 0.993 x V2/288

Cross multiply to express in linear.

295x0.993xV2 = 0.974x27.5x288

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V2 = 26.3 mL

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4 0
3 years ago
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bagirrra123 [75]

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If every oxygen ion (combined with an aluminum ion) has a charge of –2, what must the charge of each aluminum ion be? How can yo
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3 years ago
6) (a) Calculate the absorbance of the solution if its concentration is 0.0278 M and its molar extinction coefficient is 35.9 L/
Anvisha [2.4K]

Answer:

6) (a) 0.499; (b) 31.7 %

7) 0.15

Explanation:

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Beer's Law is

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7) Absorbance

A = \log \left (\dfrac{I_{0}}{I} \right ) = \log \left (\dfrac{I_{0}}{0.70I_{0}} \right ) = \log \left (\dfrac{1}{0.70} \right ) = -\log(0.70) = \mathbf{0.15}}

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Answer:

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