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Oliga [24]
3 years ago
15

Please answer this question ! thank you so much !! Will give brainliest !!

Mathematics
2 answers:
SVETLANKA909090 [29]3 years ago
5 0

Answer:

y = -7x + 14

Step-by-step explanation:

m=1/7

m perp = -7

y = mx + b

-7 = -7(3) + b

14 = b

y = -7x + 14

Bad White [126]3 years ago
3 0
Your answer going to be equal seven axis y plus sixty three
= 7y + 63
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A bird was sitting 16 feet from the base of an oak tree and flew 20 feet to reach the top of the tree. How tall is the tree?
Eddi Din [679]

Given:

A bird was sitting 16 feet from the base of an oak tree and flew 20 feet to reach the top of the tree.

To find:

The length of the tree.

Solution:

A bird was sitting 16 feet from the base of an oak tree.

Vertical distance between bird and base = 16 feet

Then the bird flew 20 feet to reach the top of the tree.

Now, the vertical distance between bird and base = (16+20) feet

So, length of the oak tree is it the sum of 16 feet and 20 feet.

\text{Length of the oak tree}=16+20 feet

\text{Length of the oak tree}=36 feet

Therefore, the length of the oak tree is 36 feet.

5 0
3 years ago
The length of a 200 square foot rectangular vegetable garden is 4feet less than twice the width. Find the length and width of th
inna [77]

Answer:

Length = 18.099 ft

Width = 11.049 ft

Step-by-step explanation:

let the length of the field be x ft

and the width be y ft

as per the condition given in problem

x=2y-4   -----------(A)

Also the area is given as 200 sqft

Hence

xy=200

Hence from A we get

y(2y-4)=200

taking 2 as GCF out

2y(y-2)=200

Dividing both sides by 2 we get

y(y-2)=100

y^2-2y=100

subtracting 100 from both sides

y^2-2y-100=0

Now we solve the above equation with the help of Quadratic formula which is given in the image attached with this for any equation in form

ax^2+bx+c=0

Here in our case

a=1

b=-1

c=-100

Putting those values in the formula and solving them for y

y=\frac{-(-2)+\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

Solving first

y=\frac{2+\sqrt{4+400}{2}

y=\frac{2+\sqrt{404}{2}

y=\frac{2+20.099}{2}

y=\frac{22.099}{2}

y=11.049

Solving second one

y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

y=\frac{2-\sqrt{4+400}{2}

y=\frac{2-\sqrt{404}{2}

y=\frac{2-20.099}{2}

y=\frac{-18.99}{2}

y=-9.045

Which is wrong as the width can not be in negative

Our width of the field is

y=11.099

Hence the length will be

x=2y-4

x=2(11.049)-4

x=22.099-4

x=18.099

Hence our length x and width y :

Length = 18.099 ft

Width = 11.049 ft

4 0
3 years ago
HELP ASAP!!! What is the slope of the line through (-1,-4) and (-6, -2)?
Mila [183]

Answer:

2/-5

Step-by-step explanation:

(-2) - (-4) = 2

(-6) - (-1) = -5

6 0
3 years ago
Read 2 more answers
What is the value of 2 in 5,014,245?
Arlecino [84]
Your reasoning and your answer were both correct. Discuss with the teacher. ("Discuss". DON'T fight.)
6 0
3 years ago
What is the result when the number 79 is decreased by 17%?
trapecia [35]

Answer:

65.57 should be the correct answer!

Step-by-step explanation:

Here is the whole work I did, hope this helps!

100 - 17 = 83

79 x 0.83 = 65.57

8 0
3 years ago
Read 2 more answers
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