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IrinaVladis [17]
2 years ago
13

Write and solve an equation for the following:

Mathematics
1 answer:
IrinaVladis [17]2 years ago
7 0

Answer:

x = (180 - [71 + 9]) ÷ 2

Step-by-step explanation:

71 + 9 = 80

180 - 80 = 100°

100° ÷ 2 = 50°

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The new function is g(x) =-1(1/-x) +2.

The transformation of function f(x) to function g(x) is given by g(x)=A f(Bx+ H)+K. where the constant A scales the function vertically. (A negative A reflects the function about the x-axis B scales the function horizontally. (A negative B reflects the function on the y-axis.) H shifts the function horizontally, and K shifts the function vertically.

Convert f(x) to g(x)

where the conversion is g(x)=f(x)+2.

A perpendicular line has negative reciprocal slopes, so for g(x) to be perpendicular to f(x), we need to get the negative reciprocal of -x, which is -1(1/-x)

So, f(x)=-x-2  ; m = -1

From the above information, we get g(x) as follows.

g(x) =-1(1/-x) +2

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Answer:

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3 years ago
Find the exact value of cos(sin^-1(-5/13))
son4ous [18]

bearing in mind that the hypotenuse is never negative, since it's just a distance unit, so if an angle has a sine ratio of -(5/13) the negative must be the numerator, namely -5/13.

\bf cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right] \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{then we can say that}~\hfill }{sin^{-1}\left( -\cfrac{5}{13} \right)\implies \theta }\qquad \qquad \stackrel{\textit{therefore then}~\hfill }{sin(\theta )=\cfrac{\stackrel{opposite}{-5}}{\stackrel{hypotenuse}{13}}}\impliedby \textit{let's find the \underline{adjacent}}

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le's bear in mind that the sine is negative on both the III and IV Quadrants, so both angles are feasible for this sine and therefore, for the III Quadrant we'd have a negative cosine, and for the IV Quadrant we'd have a positive cosine.

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3 years ago
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5 0
2 years ago
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Gary deposited $20 in a savings account earning 10% interest, compound annually. to the nearest cent, how much will he have in 3
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<h3>Answer: $26.62 </h3>

============================

Work Shown:

P = 20 is the amount deposited

r = 0.10 is the decimal form of the 10% interest rate

n = 1 means we compound 1 time per year (annually)

t = 3 is the number of years

Plug those four values into the compound interest formula below

A = P*(1+r/n)^(n*t)

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A = 20*(1+0.1)^(3)

A = 20*(1.1)^(3)

A = 20*1.331

A = 26.62

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3 years ago
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