1) its number 2. 30x^7y^4
The real zeros of a function are when the function touches or crosses the x-axis. In terms of the following linear functions, the real zeros will be the value of x when y = 0. So we simply set each equation equal to zero and solve for the x-values.
1.) y = -5x - 7
0 = -5x - 7
5x = -7
x = -7/5
The real zero is at point (-7/5, 0) and is therefore option d) -7/5.
2.) y = -7x + 3
0 = -7x + 3
7x = 3
x = 3/7
The real zero is at point (3/7, 0) and is option b.) 3/7.
3.) y = -7x + 8
0 = -7x + 8
7x = 8
x = 8/7
The real zero is at point (8/7, 0) and is option a.) 8/7.
4.) y = 3x + 1
0 = 3x + 1
-3x = 1
x = -1/3
The real zero is at point (-1/3, 0) and is option b.) -1/3.
<h2>
Angle did the helicopter take off from is 11.31°</h2>
Step-by-step explanation:
Refer the given figure.
The initial position of helicopter is A.
It needs to go to position C.
We need to find angle A.
We have
Angle did the helicopter take off from is 11.31°
Answer:
Step-by-step explanation:
-2 + 2(3) =-2 +6 = 4 for the 2nd equation
2(-2) + 4(3) = -4 +12 = 8 for the 2nd equation
(-2,3) satisfies both equations
let x = 0, then y= 2 (0,2) is another solution
there's multiple solutions, including (-2,3) and (0,2). That eliminates all answers except the first
Try graphing the two equations. They're the same line, with an infinite number of points on the line, which means an infinite number of solutions.
This is the answer 2,043,000