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3 years ago

4) A satellite is in orbit around the earth. Which one feels the greater force?

Physics

1 answer:

tresset_1 [31]3 years ago

8 0

Answer:

im pretty sure its D) ...

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A pressure cooker contains water and steam in equilibrium at a pressure greater than atmo-spheric pressure. How does this greate

Amanda [17]

Answer:

As the pressure inside the pressure cooker increases as it is heated, the temperature also increases.

Explanation:

A pressure cooker contains water and steam in equilibrium at a pressure greater than atmospheric pressure.

According to the ideal gas law, as the pressure increases, the temperature also increases.

As the pressure inside the pressure cooker increases as it is heated, the temperature also increases.

6 0

3 years ago

Why exactly do people use simple <br> machines like a pulley

Komok [63]

They can change the direction of force which can result in easier movement.

6 0

3 years ago

Two resistors of 10 and 15 n are connected. What is their combined resistance if they are connected: a) in series b) in parallel

kati45 [8]

Explanation:

Given that,

Two resistors of 10 ohms and 15 ohms are connected.

In series combination, the equivalent resistance is given by :

$R_s=R_1+R_2\\\\R_s=10+15\\\\R_s=25\ \Omega$

In parallel combination, the equivalent resistance is given by :

$\dfrac{1}{R_p}=\dfrac{1}{R_1}+\dfrac{1}{R_2}\\\\\dfrac{1}{R_p}=\dfrac{1}{10}+\dfrac{1}{15}\\\\R_p=6\ \Omega$

Hence, this is the required solution.

7 0

2 years ago

A solenoid passes through the center of a wire loop, as shown in (Figure 1). The solenoid has 1200 turns, a diameter of 2.0 cm,

atroni [7]

Answer:

true

Explanation:

just did it

4 0

3 years ago

An insulating sphere of radius 13 cm has a uniform charge density throughout its volume. 13 cm 21.6 cm 7.5 cm p If the magnitude

sdas [7]

Answer:

The value is $E_1 = 49224.1 \ N/C$

Explanation:

From the question we are told that

The radius is $r = 13 \ cm = 0.13 \ m$

The electric field is $E = 78400 \ N/C$ at a distance $d = 7.5 \ cm = 0.075 \ m$

Generally the electric field at a distance $d = 7.5 \ cm = 0.075 \ m$ is mathematically represented as

$E = \frac{k * q * d}{r^3}$ Note: the reason we are using this

formula is because $d < r$

Here k is the coulomb constant with value $k = 9*10^{9}\ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}.$

=> $78400= \frac{9*10^{9} * q * 0.075}{0.13^3 }$

Generally the electric field at a distance $d = 21.6 \ cm = 0.216 \ m$ is mathematically represented as

$E_1 = \frac{k * q }{^2}$ Note: the reason we are using this

formula is because $d > r$

Now dividing $E_1\ \ by \ \ E$

$\frac{E_1}{78400} = \frac{\frac{9*10^9 * q}{0.216^2} }{\frac{9*10^9 * q * 0.075}{0.13^3} }$

=> $E_1 = \frac{0.13 ^3}{ 0.075 * 0.216^2} * 78400$

=> $E_1 = 49224.1 \ J$

4 0

3 years ago