Question

A wire carries a current of 0.66 A. This wire makes an angle of 58° with respect to a magnetic field of magnitude 5.50 10-5 T. The wire experiences a magnetic force of magnitude 7.10 10-5 N. What is the length of the wire?

Answer 1

Answer:

The length of the wire is "1.93 m".

Explanation:

Given:

Current,

I = 0.66 A

Angle,

$\Theta$ = 58°

Magnetic field of magnitude,

F = $5.5\times 10^{-5}$ N

The length of the wire will be:

⇒ $F = B\times I\times L\times Sin \Theta$

or,

⇒ $L = \frac{F}{B\times I\times Sin \theta}$

By putting the values, we get

       $=\frac{5.5\times 10^{-5}}{0.66\times 5.1\times 10^{-5}\times Sin \ 58^{\circ}}$

       $=\frac{5.5}{2.828}$

       $=1.93 \ m$