Answer:
Base on the question , an acid and a base solution was mixed together in a crucible and all the water in the mixture was evaporated off. The only substance left in the crucible is the salt solution.
Explanation:
Acids are substances that dissolves in water to produce hydrogen ion(H⁺) while base are substances that dissolves in water to produce hydroxide ion (OH⁻).
The chemical reaction between an acid and a base solution is known as a neutralization reaction. The reaction between these 2 compounds will produce salt and water. An acid solution will react with a base solution to form salt and water. An example of this kind of reaction is between HCl (Hydrochloric acid) and NaOH(sodium hydroxide).
HCl + NaOH → NaCl + H₂O . The product form here is sodium chloride(salt) and water
Base on the question , an acid and a base solution was mixed together in a crucible and all the water in the mixture was evaporated off. The only substance left in the crucible is the salt solution. Note that the other product which is water has been evaporated and we are left with only salt solution.
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Answer:
The volume of HCl required is 
Explanation:
From the question we are told that
The chemical equation for this reaction is

The mass of Al is 
The concentration of HCl is 
The number of moles of
given is 
The molar mass of Al is 
So


From the balanced equation
2 moles of Al reacts with 6 moles of HCl
So 0.07 moles of Al will react with x
Therefore


Now the volume of HCl can be obtained as

So 

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