The dissociation of cadmium chloride is as follows: CdCl₂(s) → Cd⁺²(aq) + 2Cl⁻(aq)
<h3>What is dissociation?</h3>
Dissociation is the process by which a compound body breaks up into simpler constituents; said particularly of the action of heat on gaseous or volatile substances.
It is a chemical reaction in which a compound breaks apart into two or more components. The general formula for a dissociation reaction follows the form:
AB → A + B
According to this question, cadmium chloride undergoes dissociation into cadmium and chlorine ions as follows:
CdCl₂(s) → Cd⁺²(aq) + 2Cl⁻(aq)
Learn more about dissociation at: brainly.com/question/28952043
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This dilution problem uses the equation
M
a
V
a
=
M
b
V
b
M
a
= 6.77M - the initial molarity (concentration)
V
a
= 15.00 mL - the initial volume
M
b
= 1.50 M - the desired molarity (concentration)
V
b
= (15.00 + x mL) - the volume of the desired solution
(6.77 M) (15.00 mL) = (1.50 M)(15.00 mL + x )
101.55 M mL= 22.5 M mL + 1.50x M
101.55 M mL - 22.5 M mL = 1.50x M
79.05 M mL = 1.50 M
79.05 M mL / 1.50 M = x
52.7 mL = x
59.7 mL needs to be added to the original 15.00 mL solution in order to dilute it from 6.77 M to 1.50 M.
I hope this was helpful.
Answer:
length
Explanation:
cm measures length. Think of a ruler.
Answer:
Explanation:
percentage abundance of third isotope = 100 - ( 78.900 + 10.009)
= 11.091 %
Atomic mass
24.1687 x .789 + 25.4830 x .10009 + 24.305 x .11091
19.069 + 2.5506 + 2.69566
= 24.3153 amu
