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antoniya [11.8K]
3 years ago
10

Which were Lenin's actions before and during the Russian Revolution? Check all that apply.

Chemistry
1 answer:
Stolb23 [73]3 years ago
7 0

Answer:

He supported the ideology of Marxism.

He opposed the tsar and was exiled.

He led the Bolsheviks.

Explanation:

Lenin was Russian Revolution political theorist. He served as first founding head of government of Soviet Russia. He supported the ideology of Marxism and opposed Tsar.

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Zinc metal and aqueous silver nitrate react to give Zn(NO3)2(aq) plus silver metal. When 5.00 g of Zn(s) and solution containing
Fittoniya [83]

Answer : The percent yield is, 83.51 %

Solution : Given,

Mass of Zn = 5.00 g

Mass of AgNO_3 = 25.00 g

Molar mass of Zn = 65.38 g/mole

Molar mass of AgNO_3 = 168.97 g/mole

Molar mass of Ag = 107.87 g/mole

First we have to calculate the moles of Zn and AgNO_3.

\text{ Moles of }Zn=\frac{\text{ Mass of }Zn}{\text{ Molar mass of }Zn}=\frac{5.00g}{65.38g/mole}=0.0765moles

\text{ Moles of }AgNO_3=\frac{\text{ Mass of }AgNO_3}{\text{ Molar mass of }AgNO_3}=\frac{25.00g}{168.97g/mole}=0.1479moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

Zn+2AgNO_3\rightarrow Zn(NO_3)_2+2Ag

From the balanced reaction we conclude that

As, 2 mole of AgNO_3 react with 1 mole of Zn

So, 0.1479 moles of AgNO_3 react with \frac{0.1479}{2}=0.07395 moles of Zn

From this we conclude that, Zn is an excess reagent because the given moles are greater than the required moles and AgNO_3 is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of Ag

From the reaction, we conclude that

As, 2 mole of AgNO_3 react to give 2 mole of Ag

So, 0.1479 moles of AgNO_3 react to give 0.1479 moles of Ag

Now we have to calculate the mass of Ag

\text{ Mass of }Ag=\text{ Moles of }Ag\times \text{ Molar mass of }Ag

\text{ Mass of }Ag=(0.1479moles)\times (107.87g/mole)=15.95g

Theoretical yield of Ag = 15.95 g

Experimental yield of Ag = 13.32 g

Now we have to calculate the percent yield.

\% \text{ yield}=\frac{\text{ Experimental yield of }Ag}{\text{ Theretical yield of }Ag}\times 100

\% \text{ yield}=\frac{13.32g}{15.95g}\times 100=83.51\%

Therefore, the percent yield is, 83.51 %

7 0
3 years ago
3. A PS6 plugged into a 120 V outlet uses 3 Amps. What is the Resistance rating of
blondinia [14]

Answer:

R = 40 ohms

Explanation:

Given that,

The voltage of outlet, V = 120 V

Current flowing through the device, I = 3 A

We need to find the Resistance rating of  the power cord. Let the resistance is R. We know that,

Ohm's law, V = IR

Put all the values,

R=\dfrac{V}{I}\\\\R=\dfrac{120}{3}\\\\R=40\ \Omega

So, the resistance rating of the power cord is equal to 40 ohms.

8 0
3 years ago
Conversion of gaseous nitrogen to liquid nitrogen is an
miss Akunina [59]

Answer:

true

Explanation:

you can't change it back, it's chemically changed

8 0
3 years ago
CH3OH + O2 CO2 + H2O is this a combustion reaction?​
Brrunno [24]

Answer:

yes

Explanation:

the results are CO2 and H2O, which usually appear after some kind of combustion.(combustion=burning)

hope this helps!

3 0
3 years ago
Hii pls help me to balance chemical equation
Dominik [7]

Answer:

1 Ca(OH)2 + 2 HCl ---> 1 CaCl2 + 2 H2O

6 0
2 years ago
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