In this item, I supposed, that we are determine the molar fraction of oxygen and carbon dioxide in the sample. This can be done by dividing their respective partial pressures by the total pressure of the sample.
O2 : mole fraction = (100.7 mmHg) / (763.00 mmHg) = 0.13
CO2 : mole fraction = (33.57 mmHg) / (763.00 mmHg) = 0.044
Answers: O2 = 0.13
CO2 = 0.044
I am going to say C. it has to do with the angles
The compound is Al2O3. The ratio of aluminum to oxygen is 2:3.
410g Ag
2.3*10^24 atoms
1 molcule Ag- 6.02g*10^3
Answer:
The answer to your question is Al, Mg, Si, S, P
Explanation:
First ionization energy is the energy necessary to remove an electron from an atom in a gaseous form.
Element First ionization energy (kJ/mol)
Magnesium 737.7
Aluminum 577.5
Silicium 786.5
Phosphorus 1011.8
Sulfur 999.6
Order: Al, Mg, Si, S, P
