Hey there princesswalkeror4ori,
By far, the most abundant gas in the Earth's atmosphere<span> is </span>nitrogen<span>, which accounts for about 78% of the mass of dry air. </span>Oxygen is<span> the next most abundant gas, present at levels of 20 to 21%. Although humid air seems like it contains a lot of water, the maximum </span>amount of water vapor<span> that air can hold is only about 4%.
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Hope I helped!
Have a great day!
Answer:
The answer is "W-4 form".
Explanation:
The W-4 form is part of the Internal Revenue Service tax form, which is used to submitted by the U.S. government form the customer to information and his or her tax situation. This form informs the customer of the right amount of tax to deduct from his or her salary.
That's why she filled out a W-4 form and know-how often tax he will subtract in the payroll depending on provisions dealing, dependents, potential tax deductions, and credits, etc.
Answer:
Explanation:
pH = − log [H+] , we can solve for [H+] as,
− pH = log [H+] ,
[H+] = 10^−pH,
so PH =2.4 in you case is
[H+] = 10^-2.4 =0.00398
The option are not correct it looks
Answer:
3 e⁻ transfer has occurred.
Explanation
This is a redox reaction.
- Oxidation (loss of electrons or increase in the oxidation state of entity)
- Reduction (gain of electrons or decrease in the oxidation state of the entity)
- An element undergoes oxidation or reduction in order to achieve a stable configuration. It can be an octet or duplet configuration. An octet configuration is that of outer shell configuration of noble gas.
- [Ne]= (1s²) (2s² 2p⁶)
A combination of both the reactions( Half-reactions) leads to a redox reaction.
Let us look at initial configurations of Al and Cl
[Al]= 1s² 2s² 2p⁶ 3s² 3p¹
[Cl]= 1s² 2s² 2p⁶ 3s² 3p⁵
Hence, Al can lose 3 electrons to achieve octet config.
and, Cl can gain 1e to achieve nearest noble gas config. [Ar]
This reaction can be rewritten, by clearly mentioning the oxidation states of all the entities involved.
Al⁰ + Cl⁰ → (Al⁺³)(Cl⁻)₃
Here, Aluminum is undergoing an oxidation(i.e loss of electrons) from: 0→(+3)
Chlorine undergoes a reduction half reaction (i.e gain of electrons) from: 0→(-1). There are 3 such chlorine atoms, hence 3 e⁻ transfer has occurred.
