All categories

3 years ago

why is ammonia considered a base even though it contains no hydroxide ions. is it a strong or weak base?

1 answer:

8 0

Ammonia is a weak base because its nitrogen atom has an electron pair that readily accepts a proton. Also, when dissolved in water, ammonia acquires hydrogen ions from water to produce hydroxide and ammonium ions. It is the production of these hydroxide ions that imparts ammonia its characteristic basicity.

You might be interested in

Identify the factors that cause melting and thus the formation of magma. Choose one or more: A. decompression B. compression C.

nordsb [41]

Answer: C Heat Transfer, E Addition of Volatiles and A Decompression

Explanation:

- Decompression melting takes place within Earth when a body of rock is held at approximately the same temperature but the pressure is reduced.

8 0

4 years ago

An incompressible fluid flows steadily through a pipe that has a change in diameter. The fluid speed at a location where the pip

OverLord2011 [107]

Answer:

The value is $v_2 = 5.53 \ m /s$

Explanation:

From the question we are told

The pipe diameter at location 1 is $d = 8.8 \ cm = \frac{8.8 }{10} = 0.88 \ m$

The velocity at location 1 is $v_1 = 2.4 \ m /s$

The diameter at location 2 is $d_2 = 5.80 \ cm = 0.58 \ m$

Generally the area at location 1 is

$A_1 = \pi * \frac{d^2}{ 2}$

=> $A_1 = \pi * \frac{0.88^2}{ 2}$

=> $A_1 = 3.142 * \frac{0.88^2}{ 2}$

=> $A_1 = 1.2166 \ m^2$

Generally the area at location 1 is

$A_2 = \pi * \frac{d_1^2}{ 2}$

=> $A_2 = \pi * \frac{0.58^2}{ 2}$

=> $A_2 = 0.528 \ m^2$

Generally from continuity equation we have that

$A_1 * v_1 = A_2 * v_2$

=> $1.2166 * 2.4 = 0.528 * v_2$

=> $v_2 = 5.53 \ m /s$

3 0

3 years ago

When an experiment is replicated, how should the results of the two experiments compare?

olasank [31]

When the experiment is replicated, this means the conduction of the second experiment, should be related, or similar, to your first results.

4 0

3 years ago

Read 2 more answers

Which of the following statements about colloids is FALSE?

ycow [4]

I believe that the answer to this would be B

Hope this helped

3 0

3 years ago

On a hot day, the temperature of a 65,000-L swimming pool increases by 1.20°C. What is the net heat transfer during this heating

vichka [17]

Answer:

326149.2 KJ

Explanation:

The heat transfer toward and object that suffered an increase in temperature can be calculated using the expression:

Q = m*cv*ΔT

Where m is the mass of the object, cv is the specific heat capacity at constant volume, which basically means the amount of heat necessary for a 1kg of water to increase 1C degree in temperatur, and ΔT is the change in temperature.

A 65000 L swimming pool will have a mass of:

65000L * $\frac{1m^3}{1000L} * \frac{1000kg}{1m^3}$ = 65000 kg

The specific heat capacity at constant volume of water is equal to 4.1814 KJ/KgC.

We replace the data and get:

Q = m*cv*ΔT = 65000 kg * 4.1814 KJ/KgC * 1.2°C = 326149.2 KJ

3 0

3 years ago